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Sever21 [200]
3 years ago
8

Which of these values for P and a will cause the function f(x)=Pa^x to be an exponential growth function? (Apex) I really need h

elp thank you means a lot
A. P=2; a=1
B. P=1/2; a=1/3
C. P=1/2; a=1
D. P=2; a=3

Mathematics
2 answers:
stiks02 [169]3 years ago
7 0

Answer:

Option D

Step-by-step explanation:

Consider the four options being substituted

A) 2(1^x) = 2 will be option I which is a constant function

B) f(x) = \frac{1}{2}(\frac{1}{3}  )^x

But here since a <1 we find this is a decay function

C) Here since a=1 this is a constant funciton.

D) . P=2; a=3

f(x) = 2(3)^X

As x increases by 1, we get f(x) increases by 3 times

Hence this is exponential growth

prisoha [69]3 years ago
4 0

Answer:

i am not to positive but i think its C

Step-by-step explanation:

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Answer:

<C = 133 degrees

Step-by-step explanation:

<B = 90 - 43

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3 years ago
Which sequence is modeled by the graph below? coordinate plane showing the points 1, 2; 2, 2; 3, 2; 4, 2
prisoha [69]

We will start with plotting the x coordinates and y coordinates on the graph

The points 1, 2; 2, 2; 3, 2; 4, 2  have been plotted on the graph which has been attached as an image to the solution.

We can see that the value of y is staying constant (2) for all values of x.

Hence, the points represent the equation y = 2.

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Answer:

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3 years ago
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PLS HELP ME!!! The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of
Pachacha [2.7K]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

What is the approximate volume of this figure?

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{V = 334.93\:cm^3 \to Volume\:of\:the\:figure \approx 335\:cm^3 }}}\end{array}}\qquad\quad\checkmark

Answer:

The volume of the figure is approximately 335 cm³

_______________________

I Hope this helps, greetings ... Dexteright02! =)

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SVEN [57.7K]

Answer:

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Step-by-step explanation:

3 0
2 years ago
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