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xeze [42]
3 years ago
5

Sarah is making a scale drawing of a painting that is 48 in. wide by 120 in. high. Her paper is 12 in. wide and 24 in. tall. She

decides to use the scale 1 in. = 4 in. Is this a reasonable scale?
Please show all work thank you.
Mathematics
2 answers:
romanna [79]3 years ago
8 0

Answer:

The scale is not reasonable .

Step-by-step explanation:

We are given that Sarah is making a scale drawing of a painting that is 48 in. wide by 120 in. high.

Her paper is 12 in. wide and 24 in. tall.

Scale :  1 in. = 4 in.

Since 1 inch = 4 inch

So, 12 inch = 12\times 4 = 48 inches

24 inch = 24\times 4 =96 inches

The given scale is not reasonable because the scale is true for the width but false for the height

Since the actual height is 120 inches and we are getting 96 inches using the given scale .

Hence the scale is not reasonable .

noname [10]3 years ago
3 0
48 / 12 = 4
120 / 24 = 5

This is not a reasonable scale because ratios of tall and wide are not proportional.

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A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

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Remember that for a general quadratic equation:

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The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

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the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

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df(x)/dx = n*a*x^(n-1)

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v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

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So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

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Answer:

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