The funds in the account remain for as long as you’re employed by the company sponsoring the FSA.
The area of the circle is 28 ft square.
The area of the triangle is 30 ft square.
Step-by-step explanation:
1) The area of the circle= π*r^2
where π= 3.14(default value) and "r" is the radius of the circle.
Here, Radius of the circle(r)= 3 ft
Area = 3.14*3*3
= 28.26 ft sq.= 28 ft sq(rounded to the nearest whole number)
2) The triangle has the base= 10 feet and height= 6 feet
The Area of the triangle= 1/2(b)(h)
where "b" is the base and "h" is the height of the triangle.
Substitute b=10 and h=6 ,
Area of triangle= 1/2(10 ft)(6 ft)= 60/2= 30 feet sq.
Answer:
0.000001
Step-by-step explanation:
It is because 10 is represented as just like 10 and then in a certain place. And then the negative means it is to the right of the decimal. 6th power means the 6th place. So, basically it means, 10 in the 6th to the right place which is 0.0000010. You do not need the last zero because there is no value after that, so 0.000001.
Sorry if I am wrong! Can I be brainlieest? TYSM
Answer:
m∠BCE = 28° and m∠ECD = 134°
Step-by-step explanation:
* Lets explain how to solve the problem
- The figure has three angles: ∠BCE , ∠ECD , and ∠BCD
- m∠ECD is six less than five times m∠BCE
- That means when we multiply measure of angle BCE by five and
then subtract six from this product the answer will be the measure
of angle ECD
∴ m∠ECD = 5 m∠BCE - 6 ⇒ (1)
∵ m∠BCD = m∠BCE + m∠ECD
∵ m∠BCD = 162°
∴ m∠BCE + m∠ECD = 162 ⇒ (2)
- Substitute equation (1) in equation (2) to replace angle ECD by
angle BCE
∴ m∠BCE + (5 m∠BCE - 6) = 162
- Add the like terms
∴ 6 m∠BCE - 6 = 162
- Add 6 to both sides
∴ 6 m∠BCE = 168
- Divide both sides by 6
∴ m∠BCE = 28°
- Substitute the measure of angle BCE in equation (1) to find the
measure of angle ECD
∵ m∠ECD = 5 m∠BCE - 6
∵ m∠BCE = 28°
∴ m∠ECD = 5(28) - 6 = 140 - 6 = 134°
* m∠BCE = 28° and m∠ECD = 134°
-x-8y+5
Hope this helps, we have same name btw
