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4 years ago

7.6g of sugar is needed for every cake made. How much sugar is needed for 10 cakes?

Mathematics

1 answer:

nexus9112 [7]4 years ago

3 0

If u need 7.6 grams of sugar for every cake....then for 10 cakes, u would need : 7.6 * 10 = 76 grams <==

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Which number is a solution of the inequality? 3x – 15 ≥ 3

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Answer:

A. 6

Step-by-step explanation:

3x – 15 ≥ 3

Add 15 to both sides

3x ≥ 18

Divide both sides by 3

x ≥ 6

So solutions are any numbers greater than or equal 6

Answer:

A. 6

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assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

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Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

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3 years ago