<em>Greetings from Brasil</em>
From radiciation properties:
![\large{A^{\frac{P}{Q}}=\sqrt[Q]{A^P}}](https://tex.z-dn.net/?f=%5Clarge%7BA%5E%7B%5Cfrac%7BP%7D%7BQ%7D%7D%3D%5Csqrt%5BQ%5D%7BA%5EP%7D%7D)
bringing to our problem
![\large{6^{\frac{1}{3}}=\sqrt[3]{6^1}}](https://tex.z-dn.net/?f=%5Clarge%7B6%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B6%5E1%7D%7D)
<h2>∛6</h2>
If 1 of ur factors is 9...and the sum of ur factors is 13....then ur other factor is (13 - 9) = 4
so u have 2 factors, 9 and 4, and u r the product, then u r (9 * 4) = 36 <==
Equation of a circle:
(x - h)^2 + (y - k)^2 = r^2
In this case:
<span>center (2,7) and radius 4 so h = 2, k = 7 and r = 4
</span>Equation:
(x - 2)^2 + (y - 7)^2 = 4^2
(x - 2)^2 + (y - 7)^2 = 16
Hope it helps.
Answer:-23
Step-by-step explanation:
The number of ways to arrange the 5 writings in a row is 5! = 5 * 4 * 3 * 2 * 1 = 120 ways.
There is only 1 way to arrange the writings from oldest to newest.
Therefore, the probability is 1/120.
