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Maslowich
3 years ago
7

What shape best describes the cross section cut parallel to the base of a right rectangular prism?

Mathematics
2 answers:
Alex787 [66]3 years ago
6 0
To answer this question, it is enough to find the volume of a rectangular prism.
 The volume of a rectangular prism is:
 V = Ab * h

 Where,
 Ab: base area
 h: height
 The area of the base is:
 Ab = w * l

 Where,
 w: width
 l: long
 We observe that the area of the base is a rectangle, therefore, the section parallel to the base is also a rectangle.
 Answer: 
 The cross section cut parallel to the base of a right rectangular prism is:
 Rectangle
nlexa [21]3 years ago
4 0
<span>The cross section of a rectangular prism is a rectangle. The cross section is the shape that results from cutting straight through a prism.</span>
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dimensions of a building are 740 feet by 800 feet. If 1inch represents 8 feet. What are the dimensions of the building on the dr
nevsk [136]

Answer: 92.5 inches by 100 inches.


Step-by-step explanation:

1. You know that 1 inch represents 8 feet and the dimensions of the building are 740 feet by 800 feet, therefore, you must apply the proccedure shown below:

\frac{740ft*1in}{8ft}=92,5in

\frac{800ft*1in}{8ft}=100in

2. Then, as you can see, the dimensions of the building on the drawing are 92.5 inches by 100 inches.


6 0
3 years ago
A water sprinkler sends water out in a circular pattern. How many feet away from the sprinkler can it spread water if the area f
myrzilka [38]

Answer:

The sprinkler can spread water 18 feet away.

Step-by-step explanation:

We are given the following in the question:

Area formed by watering pattern = 1,017.36 square feet

We have to find the how far the sprinkler spread the water.

The sprinkler covers a circular area. We need to find the radius of this circular area to find the how far the sprinkler spread the water.

Area of circle =

A = \pi r^2

where r is the radius of the circle.

Putting values, we get,

1017.36 = 3.14 r^2\\\\r^2 = \dfrac{1017.36}{3.14}\\\\r^2 = 324\\r = \sqrt{324} = 18\text{ feet}

Thus, the sprinkler can spread water 18 feet away.

6 0
3 years ago
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u⁷

Step-by-step explanation:

When multiply variables with exponents , all you do is add the exponents

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Adding the powers is 7

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2 years ago
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2 years ago
Find dy/dx if y =x^3+5x+2/x²-1
stiks02 [169]

<u>Differentiate using the Quotient Rule</u> –

\qquad\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\

According to the given question, we have –

  • f(x) = x^3+5x+2
  • g(x) = x^2-1

Let's solve it!

\qquad\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\

\qquad\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2)  \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\

\qquad\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5)  -  ( x^3+5x+2) 2x}{(x^2-1)^2 }\\

\qquad\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\

\qquad\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\

\qquad\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\

\qquad\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\

\qquad\pink{\therefore  \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}}  =  \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\

7 0
2 years ago
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