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3 years ago

This distance-time graph represents a journey made by Jo.

Mathematics

1 answer:

ioda3 years ago

6 0

Answer:

Jo started decelerating at the 10th minute

His average speed for the last 30 minutes of the journey is 4/30 km/minute

Step-by-step explanation:

To get what Jo did at 10 minute, we look at the graph.

At the 10th minute, we can see that we have a sharp turn from the top to the zero position at the 20th minute

so we can say that Jo started deceleration at the 10th minute

For the last 30 minutes of the journey, he travelled a distance of 4km

So, mathematically, his average speed will be;

Distance/ time = 4km/30 minutes = 4/30 km/minute

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F(x)=11x -x +2 find the potential rational zeros

d1i1m1o1n [39]

X = - 1/2

In other way is x = -0.2 , x = -5^-1

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2 years ago

HELP HELP HELP HELP HELP PLSSSSSSSS

valentinak56 [21]

Answer:

I have no idea. Umm maybe ask your mom. Or dad do either of them know math?

U could try to email your teacher.

Step-by-step explanation:

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2 years ago

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A rectangular sticker has an area of 50 square centimeters. Its perimeter is 30 centimeters. What are the dimensions of the stic

Nata [24]

Length + width = 1/2 the perimeter:30/2 = 15

Area = length x width

List the factors of 50: 1, 2, 5, 10, 25, 50.

Find the two factors that when added together equal 15:

Dimensions are 5 cm by 10 cm.

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2 years ago

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On its municipal website, the city of Tulsa states that the rate it charges per 5 CCF of residential water is $21.62. How do the

Daniel [21]

Answer:

hello your question is incomplete attached below is the complete question

answer :

H0 : u = 21.62 ( Null hypothesis )

H1 : u = 21.62 ( alternative hypothesis )

Step-by-step explanation:

Formulating hypothesis that can be used to determine whether the population mean rate at 5 CCF of residential water discharged by U.S public utilities differs from $21.62

H0 : u = 21.62 ( Null hypothesis )

H1 : u = 21.62 ( alternative hypothesis )

3 0

3 years ago

Someone help ASAP!!!!!!

Alchen [17]

Answer:

Length, l = 11 ft.

Width, w = 9 ft.

Step-by-step explanation:

From the given data, the area of the rectangle = 99 ft².

Area of the rectangle = Length, l X Width, w

Here, Length, l = 7 more than twice the width

⇒ Length, l = 7 + 2w

Therefore, Area, A = 99 = (7 + 2w)w

⇒ 99 = 7w + 2w²

⇒ 2w² + 7w - 99 = 0

Solve the Quadratic equation using the formula: x = $\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ for the quadratic equation ax² + bx + c = 0.

Therefore, w = $\frac{-7 \pm \sqrt{7^2 -4(2)(-99)}}{2(2)}$

$= \frac{-7 \pm \sqrt{49 + 8(99)}}{4}$

$= \frac{-7 \pm + \sqrt{841}}{4}$

Since, $\sqrt{841} = 29$ we get:

$w = \frac{-7 \pm 29}{4}$

This gives two values of 'w', viz., w = $\frac{-7 - 29}{4}$ , $\frac{-7 + 29}{4}$

$\implies w = \frac{22}{4}, \frac{-36}{4}$

⇒ w = $\frac{22}{4}$ , -9.

We take the integer values.

If w = -9, then l = 2(-9) + 7

⇒ l = - 18 + 7 = - 11

Therefore, the length, l of the rectangle = - 11 ft.

and the width, w of the rectangle = - 9 ft.

Hence, the answer.

3 0

2 years ago