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Phoenix [80]
3 years ago
8

Solve 235 + 123 on a number line

Mathematics
1 answer:
bekas [8.4K]3 years ago
7 0
This is easy so you first get your number line and you put 235 on top of the number line and on the botton you put 123 them your make a seperate equestion and add 235 + 123 = 358 and add the nuber 358 in the middle and put right next to 358 final answer
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Slope -3/4, through (-2,4)
exis [7]

Answer:

I assume you want the equation for the line in y=mx+b form, if not, you can just transfer this form to standard or intercept. y=(-3/4)x+2.5

Step-by-step explanation:

Since you have the slope and a point, plug in the points to the equation y=9-3/4)x+b to get 4=(-3/4)(-2)+b and solve.

8 0
3 years ago
Find the derivative of <br><img src="https://tex.z-dn.net/?f=%20y%20%3D%20%5Csqrt%5B3%5D%7Bx%7D%20" id="TexFormula1" title=" y =
MAXImum [283]

Answer:

\displaystyle y'(27) = \frac{1}{27}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Exponential Rule [Root Rewrite]: \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}
  • Exponential Rule [Rewrite]: \displaystyle b^{-m} = \frac{1}{b^m}

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

y = ∛x

x = 27

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Root Rewrite]:                               \displaystyle y = x^{\frac{1}{3}}
  2. Basic Power Rule:                                                                                         \displaystyle y' = \frac{1}{3}x^{\frac{1}{3} - 1}
  3. Simplify:                                                                                                         \displaystyle y' = \frac{1}{3}x^{-\frac{2}{3}}
  4. Rewrite [Exponential Rule - Rewrite]:                                                           \displaystyle y' = \frac{1}{3x^{\frac{2}{3}}}

<u>Step 3: Solve</u>

  1. Substitute<em> </em>in <em>x</em> [Derivative]:                                                                           \displaystyle y'(27) = \frac{1}{3(27)^{\frac{2}{3}}}
  2. Evaluate exponents:                                                                                     \displaystyle y'(27) = \frac{1}{3(9)}
  3. Multiply:                                                                                                         \displaystyle y'(27) = \frac{1}{27}

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

8 0
3 years ago
Use the calculator to find the product. (1. 466 × 10–8)(5. 02 × 105) What is the coefficient of the product? What is the exponen
mestny [16]

The product of the factors in the given expression comes to be 7.35932 *10^{-3}.

The given expression is:

(1.466*10^{-8} )(5.02*10^5)

We can rewrite the given expression as

(1.466*5.02)(10^{-8} *10^5)

<h3>What is the exponent addition rule? </h3>

If we have two numbers with the same base we can write the product of the numbers as a single base followed by the addition of exponents.

a^m*a^n = a^{m+n}

1.466*5.02=7.35932

10^{-8} *10^5 = 10^{-3}....from exponent addition rule

So, (1.466*10^{-8} )(5.02*10^5)=7.35932 *10^{-3}

Therefore, the product of the factors in the given expression comes to be 7.35932 *10^{-3}.

To get more about exponents visit:

brainly.com/question/819893

6 0
2 years ago
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The hypotenuse of right triangle ABC is represented by segment AB, as shown on the graph.
icang [17]
Point C can be located on points (-3,2)
8 0
3 years ago
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Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 blanket per d
Sauron [17]

Answer:

Since Darcie wants to crochet a minimum of 3 blankets and she crochets at a rate of 1/5 blanket per day, we can determine how many days she will need to crochet a minimum of 3 blankets following the next steps:

- Finding the number of days needed to crochet one (1) blanket:

\begin{gathered}1=\frac{1}{5}Crochet(Day)\\Crochet(Day)=5*1=5\end{gathered}

1=

5

1

Crochet(Day)

Crochet(Day)=5∗1=5

So, she can crochet 1 blanket every 5 days.

- Finding the number of days needed to crochet three (3) blankets:

If she needs 5 days to crochet 1 blanket, to crochet 3 blankets she will need 15 days because:

\begin{gathered}DaysNeeded=\frac{NumberOfBlankets}{Rate}\\\\DaysNeeded=\frac{3}{\frac{1}{5}}=3*5=15\end{gathered}

DaysNeeded=

Rate

NumberOfBlankets

DaysNeeded=

5

1

3

=3∗5=15

- Writing the inequality

If she has 60 days to crochet a minimum of 3 blankets but she can complete it in 15 days, she can skip crocheting 45 days because:

AvailableDays=60-RequiredDaysAvailableDays=60−RequiredDays

AvailableDays=60-15=45DaysAvailableDays=60−15=45Days

So, the inequality will be:

s\leq 45s≤45

The inequality means that she can skip crocheting a maximum of 45 days since she needs 15 days to crochet a minimum of 3 blankets.

Have a nice day!

3 0
3 years ago
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