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Phoenix [80]
3 years ago
8

Solve 235 + 123 on a number line

Mathematics
1 answer:
bekas [8.4K]3 years ago
7 0
This is easy so you first get your number line and you put 235 on top of the number line and on the botton you put 123 them your make a seperate equestion and add 235 + 123 = 358 and add the nuber 358 in the middle and put right next to 358 final answer
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Which value is equivalent to 93.982<br> ОА 911<br> o<br> B<br> 924<br> O c 8111<br> c
notka56 [123]
A 9^11. Or, nine to the eleventh power
5 0
2 years ago
HELP!!! Which of the following is not a perfect square trinomial? A. 169 – 26y + y2 B. 81 + 18y + y2 C. 64 + 8y + y2 D. 25 + 10y
natita [175]
Let's review the options:
A. 169-26y+y^2 can be factorised into (13-y)(13-y)
B. 81+18y+y^2 can be factorised into (9+y)(9+y)
C. 64+8y+y^2 cannot be factorised into double brackets
D. 25+10y+y^2 can be factorised into (5+y)(5+y)

Therefore your answer is the odd one out, C.
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3 years ago
Find x so the distance between (x , 7) and (5, – 7) is 296​
tatuchka [14]

Answer:

Step-by-step explanation: lets have sex pls i need it

4 0
3 years ago
To determine whether the means of two populations are equal,
worty [1.4K]

Answer:

The correct option is C. either a t test or an analysis of variance can be performed.

Step-by-step explanation:

Consider the provided information.

  • The t-test, is used for whether the means of two groups are equal or not. The assumption for the test is that both groups are sampled from normal distributions with equal variances.
  • Analysis of Variance (ANOVA) is a statistical method evaluating variations between two or more methods. ANOVA is used in a study to analyze the gaps between group methods.
  • ANOVA is used not for specific differences between means, but for general testing.
  • The chi-squared test is often used to evaluate whether there was a significant difference in one or more groups between the predicted frequencies and the observed frequencies.

Hence, Either a t test or an analysis of variance can be performed to determine whether the means of two population are equal.

Therefore, the correct option is C. either a t test or an analysis of variance can be performed.

4 0
3 years ago
Solve 16(t - 1) + 10 &gt; 8(t + 2) + 4(t - 1) + 4t.
Neporo4naja [7]

Answer:

The answer to your question is it has no solution

Step-by-step explanation:

Inequality

                   16(t - 1) + 10 > 8(t + 2) + 4(t - 1) + 4t

-Expand

                   16t - 16 + 10 > 8t + 16 + 4t - 4 + 4t

- Group like terms

                   16t - 8t - 4t - 4t > 16 - 4 + 16 - 10

-Simplify

                                       0 > 18

- It has no solution because the variable is cancelled.

3 0
3 years ago
Read 2 more answers
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