It would be 2,5, and 6. The mode means the number that is repeating the most. Since 2, 5, and 6 all appear 3 times, that is the mode
I think the answer is A.
It's probably wanting you to use pythagorean theorem.
A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
Learn more about translation rule:
brainly.com/question/15161224
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Answer:
No x^3 times x^5 is not equal to x^15. It is equal to x^8
Step-by-step explanation:
x3x5
=x3*x5
=(x*x*x)*(x*x*x*x*x)
=x*x*x*x*x*x*x*x
=x8
Answer:
455
Step-by-step explanation:
455×10²
P:$2,275
R:4%
T:5
P:$2,275
subtitle:R: 4%into formula
T:5
5×2275×0.04
5×(2275×0.04)
5×91
answer:455
