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makkiz [27]
4 years ago
5

Need help ASAP ?!!!!

Mathematics
1 answer:
natulia [17]4 years ago
8 0

So remember that the area of a circle is A = π * r^2, with r = radius. In this case, the radius is 1.5, and with that info our equation is A = π * 1.5^2 .


For this, all you need to do is solve the exponents, and your answer is A = 2.25π yds^2

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ale4655 [162]
Yes the answer is c. z=3 or z=-9
3 0
3 years ago
PLEASE HELP!!!!
Lunna [17]

NOTES:

Given a quadratic function in standard format (y = ax² + bx + c), the direction of the parabola is as follows:

  • if "a" is positive, then opens UP
  • if "a" is negative, then opens DOWN

Given a quadratic function in standard format (y = ax² + bx + c), the vertex can be found as follows:

  • the Axis Of Symmetry (x-value) is: x = \frac{-b}{2a}  
  • y-value is found by plugging in the AOS for "x" in the equation

****************************************************************************************

1) y = x² + 11x + 24

  • a = +1 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-11}{2(1)}  = -\frac{11}{2}
  • y = (-\frac{11}{2})^{2} + 11(-\frac{11}{2} ) + 24 = -\frac{25}{4}
  • vertex (-\frac{11}{2}, -\frac{25}{4}) is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-3, 0) and (-8, 0), and y-intercept (0, 24)

******************************************************************************************

2) y = -x² - 6x - 8

  • a = -1 so the parabola opens DOWN
  • x = \frac{-b}{2a} = \frac{-(-6)}{2(-1)}  = \frac{6}{-2} = -3
  • y = -(-3)² - 6(-3) - 8 = -9 + 18 - 8 = 1
  • vertex (-3, 1) is in Quadrant 2 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-4, 0), and y-intercept (0, -8)

******************************************************************************************

3) y = x² - 2x + 3

  • a = 1 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-(-2)}{2(1)}  = \frac{2}{2} = 1
  • y = (1)² - 2(1) + 3 = 1 - 2 + 3 = 2
  • vertex (1, 2) is in Quadrant 1 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 3), and its mirror image (2, 3). <em>There are no x-intercepts</em>

******************************************************************************************

4) y = x² + 4x + 4

  • a = 1 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-4}{2(1)}  = -2
  • y = (-2)² + 4(-2) + 4 = 4 - 8 + 4 = 0
  • vertex (-2, 0) is in Quadrant 2 and is on the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 4), and its mirror image (-4, 4). <em>The x-intercept is the vertex.</em>

Compared to the other four graphs, this is most likely the equation for the rain gauge!

******************************************************************************************

5) y = 3x² + 21x + 30

  • a = +3 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-21}{2(3)}  = -\frac{7}{2}
  • y = 3(-\frac{7}{2})^{2} + 21(-\frac{7}{2} ) + 30 = -\frac{27}{4}
  • vertex (-\frac{7}{2}, -\frac{27}{4}) is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-5, 0), and y-intercept (0, 30)

*******************************************************************************************

4 0
4 years ago
Read 2 more answers
Y + 6 = 5(x - 4)<br>Write the formula for f(x) in terms of x​
Mandarinka [93]

The formula for f(x) in y + 6 = 5(x - 4) in terms of x is f(x) = 5(x - 4) - 6

5 0
2 years ago
Read 2 more answers
Jamie says the value of the expression 1.43 × (−
irinina [24]

Jamie's estimate is reasonable.

Explanation:

The expression is 1.43 \times\left(-\frac{16}{31}\right)

Dividing the term \left(-\frac{16}{31}\right), we get,

1.43 \times(-0.51613)

Multiplying the terms, we have,

-0.7380659

But, Jamie's estimate is -0.75

The difference between the two values is 0.0119341 which is negligible.

Hence, Jamie's estimate is reasonable.

3 0
4 years ago
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