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3 years ago

6

The measures of the angles of a triangle are shown in the figure below. Solve for x.

2 answers:

Margarita [4]3 years ago

8 0

Answer:

66 degrees

Step-by-step explanation:

All triangles have 180 degrees spread across 3 interior angles. To find the third angle add the other 2 then subtract that number by 180.

44+70=114

180-114=66

morpeh [17]3 years ago

3 0

Answer:

63

Step-by-step explanation:

40+77=117

180-117=63

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Verify that the following equation is an identity. (1/sinx) - (1/cscx) = cscx - sinx

Anarel [89]

Manipulating the left side of the equation, we obtain:

$\dfrac{1}{\sin x}-\dfrac{1}{\csc x}=\dfrac{\csc x-\sin x}{\sin x\cdot\csc x}$

Using that $\csc x=\dfrac{1}{\sin x}$ :

$\dfrac{\csc x-\sin x}{\sin x\cdot\csc x}=\dfrac{\csc x-\sin x}{\sin x\cdot\dfrac{1}{\sin x}}=\dfrac{\csc x-\sin x}{1}=\csc x-\sin x\\\\\boxed{\dfrac{1}{\sin x}-\dfrac{1}{\csc x}=\csc x-\sin x}~~\blacksquare$

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3 years ago

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The Big Telescope Company sells circular mirrors. Their largest mirrors have radii of 5 meters and their smallest mirrors have r

pogonyaev

Answer: 1:5

Step-by-step explanation:

Given: The cost of every mirror is proportional to the cube of the mirror's radius.

i.e. $\dfrac{\text{Cost of smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{(\text{radii of smallest mirror}^3)}{\text{(radii of largest mirror)}^3}$

Their largest mirrors have radii of 5 meters and their smallest mirrors have radii of 1 meter.

Then,

$\dfrac{\text{Cost of smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{1^3}{(5)^3}=\dfrac{1}{125}$

The ratio of the total cost of 25 of the company's smallest mirrors to the cost of one of the company's largest mirrors will be:

$\dfrac{\text{Cost of 25 smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{25\times 1}{125}=\dfrac{1}{5}$

Hence, the ratio of the total cost of 25 of the company's smallest mirrors to the cost of one of the company's largest mirrors = 1:5 .

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3 years ago

A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45

Lapatulllka [165]

The train will pass the jogger in 36 seconds.

Length of train = 120m

Speed of train = 45kmph

Distance by which the jogger is ahead of the engine of the train = 240 m

Speed of jogger = 9 kmph

To pass the jogger, the train will have to cover the length of the train and the distance by which the jogger is ahead of the engine of train.

Hence,

Distance = 120 + 240 = 360m

As,

Time = Distance/Speed

Relative speed of train w.r.t jogger = 45 - 9 = 36 kmph = 10 m/s

Hence,

Time = 360/10 = 36 seconds.

To learn more about train, here:-

brainly.com/question/21218609

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1 year ago

VLD [36.1K]

Answer:

y=-1/5x+1

Step-by-step explanation:

divide both sides by 5: 1/5x+y=1

subtract 1/5x so y is alone since slope-intercept has y=mx+b: y=-1/5x+1

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3 years ago

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Alex787 [66]

Answer:

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Step-by-step explanation:

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