Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
The answer to your question is 3n+5
Answer:
20100
Step-by-step explanation:
There are 200 numbers in this addition problem. To add this, we can do 1 + 200, 2 + 199, 3 + 198 and so on. All of these pairs have a sum of 201 and since there are 200 / 2 = 100 pairs the answer is 201 * 100 = 20100.
Answer:
At first, we have 3 expressions that are equal.
This is not true.
To easily find the slope from standard form (Ax + By = C) use -A/B
1. m = -5/3
2. m = -3/5
perpendicular slopes are negative reciprocals, which these are not
parallel slopes are exactly the same, which these are also not
so, these equations are neither parallel nor perpendicular
