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shtirl [24]
3 years ago
11

20 POINTS!!!

Mathematics
1 answer:
slamgirl [31]3 years ago
3 0

Try graphing using the x-intercept and y-intercept.


-15x - 5y = 45

Put in x = 0 to get -5y = 45, making y = -9. Point (0, -9) is on the line.

Put in y = 0 to get -15x = 45, making x = -3. Point (-3, 0) is on the line.


-2x + 6y = 6

Put in x = 0 to get 6y = 6, making y = 1. Point (0, 1) is on the line.

Put in y = 0 to get -2x = 6, making x = -3. Point (-3, 0) is on the line.


(We've actually stumbled on the solution since (-3, 0) is on both lines!)


Graph the two lines using the points found above.


The solution is x = -3, y = 0.

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-6x +20 &gt;= -11x <br> solve the inequality
frez [133]

Answer:

<h2>x≥-4 </h2>

Step-by-step explanation:

plz i need brailyesit

8 0
3 years ago
-3x^2 plus 24x = 27 <br> complete the square
Rudik [331]

You can divide the whole expression by -3:

-3x^2+24x=27 \iff x^2-8x = -9

Recalling that

(x-a)^2=x^2-2ax+a^2

Let's compare the middle term:

-8x = -2ax \iff a=4

So, we want to complete

(x-4)^2 = x^2-8x+16

Which differs from x^2-8x by 16. So, if we add 16 to both sides, we have

x^2-8x=-9 \iff x^2-8x+16=7 \iff (x-4)^2=7

3 0
3 years ago
Read 2 more answers
The average of six numbers is 4. If the of two of those numbers is 2, what is the average of the other four numbers?
matrenka [14]

Answer:

5

Step-by-step explanation:

total sum of the 6 numbers

= 4 ×6

= 24

sum of numbers without the two 2s

= 24 - 2(2)

= 20

average of other 4 numbers

= 20 ÷ 4

= 5

6 0
3 years ago
Wrich expreson is equivalent to 4(3-6).​
Korvikt [17]
You haven’t provided any option, however I think I can still help.

You can solve 4(3-6). You first deal with he parenthesis, and get 4(-3). This means that your expression is equivalent to -12.


Hope this helps :)
8 0
3 years ago
Find the area of each figure. Pls, this is urgent, I will award brainliest.
Crazy boy [7]

Answer:

The area of the figure is;

A = 2,112 in²

Step-by-step explanation:

The given figure is a composite figure consisting of a rectangle AINE and a triangle AIL

The dimensions of the rectangle AINE are;

Length, L = 48 in.

Height, h = 32 in.

The area of the rectangle AINE, A₁ = Length, L × Height, h

∴ A = L × h = 48 in. × 32 in. = 1,536 in.²

The area of the triangle AIL, A₂ = 1/2 × Base × Height of the triangle

The base length of the triangle, L = IA = 48 in.

The height of the triangle, ht = 12 in.

∴ A₂ = L × ht

A₂ = 48 in. × 12 in. = 576 in.²

The area of the triangle AIL, A₂ = 576 in.²

The area of the figure, A = The area of the rectangle, A₁ + The area of the triangle, A₂

A = A₁ + A₂

∴ A = 1,536 in.² + 576 in.² = 2,112 in.²

The area of the figure, A = 2,112 in².

4 0
3 years ago
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