Question

The length of a spring varies directly with the mass of an object that is aftached to it. When a 30-gram object is attached, the

Answer 1

Answer:

s = $\frac{3}{10}$ m

Step-by-step explanation:

Given s varies directly with m then the equation relating them is

s = km ← k is the constant of variation

To find k use the condition s = 9 when m = 30 , thus

9 = 30k ( divide both sides by 30 )

k = $\frac{9}{30}$ = $\frac{3}{10}$

s = $\frac{3}{10}$ m ← equation of variation