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4 years ago

26•26^8 i’m not sure how to solve this

Mathematics

2 answers:

alexira [117]4 years ago

7 0

Answer:

26^9

Step-by-step explanation:

Dmitrij [34]4 years ago

7 0

Answer:
=26^9

Explanation: If a term doesn't have an exponent, it is considered that the exponent is Multiply the terms with the same base by adding their exponents. Add the numbers.

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Rewrite each expression by completing the square q^2+12q+32

julia-pushkina [17]

The given expression can be written as $q^{2} +12q+32$ = (q+8)(q+4).

Step-by-step explanation:

Given,

$q^{2} +12q+32$

To make it a complete square.

Formula

(a+b)² = $a^{2} +2ab+b^{2}$

$a^{2} -b^{2} = (a+b)(a-b)$

Now,

$q^{2} +12q+32$

= $q^{2} +2.q.6+6^{2} -6^{2} +32$

= (q+6)²-36+32

= (q+6)²-4

= (q+6)²-2²

= (q+6+2)(q+6-2)

= (q+8)(q+4)

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3 years ago

On a coordinate graph, what is the distance between (-10,2) and (-10,7)?<br> PLEASE HELP ME

Lady_Fox [76]

Answer:

the distance is five units up!

Step-by-step explanation:

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3 years ago

Determine the possible side lengths of the third side of a triangle with known side lengths of 5 and 8.

andre [41]

Answer:

Step-by-step explanation:

8 times 5=40

8 0

3 years ago

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seropon [69]

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3 years ago

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Use the quadratic formula to find both solutions to the quadratic equation given below 3x^2-x+5=0

lora16 [44]

For this case we have the following quadratic equation:

$3x ^ 2-x + 5 = 0$

We have to:

$a = 3\\b = -1\\c = 5$

The quadratic equation states that:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Substituting the values we have:

$x = \frac {- (- 1) \pm \sqrt {(- 1) ^ 2-4 (3) (5)}} {2 (3)}\\x = \frac {1 \pm \sqrt {1-60}} {6}\\x = \frac {1 \pm \sqrt {-59}} {6}\\x = \frac {1 \pm \sqrt {59i ^ 2}} {6}\\x = \frac {1 \pm i \sqrt {59}} {6}$

We have two roots:

$x_ {1} = \frac {1 + i \sqrt {59}} {6}\\x_ {2} = \frac {1-i \sqrt {59}} {6}$

Answer:

$x_ {1} = \frac {1 + i \sqrt {59}} {6}\\x_ {2} = \frac {1-i \sqrt {59}} {6}$

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3 years ago