A triangle has these side lengths:

A used car dealer sells SUVs and cars. Of all the vehicles, 85% are cars. Of all the vehicles, 32% are red cars. What is the pro

oksian1 [2.3K]

Answer:

37.6%

Step-by-step explanation:

P(A|B) = P(A and B) / P(B)

P(red | car) = P(red and car) / P(car)

P(red | car) = 0.32 / 0.85

P(red | car) = 0.376

8 0

3 years ago

(07.05 HC)

lianna [129]

Answer:

c

Step-by-step explanation:

2×8=16

not 10 that is why c is correct

8 0

3 years ago

CAN SOMEONE HELP ME WITH THIS PLEASE AND THANK YOU

sammy [17]

For this do 5/8-1/2!! in order to do this, find the common denominator. this one is 16, so do: 10/16-8/16, and simplify!

5 0

3 years ago

Read 2 more answers

But whats the answer

Gekata [30.6K]

Question: Mia and Kai want to rent a canoe at the boathouse on the river. It costs $6.95 to rent a canoe for 1 hour. The price per hour stays the same for up to 3 hours of rental. After 3 hours, the cost decreases to $4.50 per hour. How much would it cost Mia and Kai to rent a canoe for 4 hours?

Answer:

$23.30

Step-by-step explanation:

To do this I did 6.45(3) + 6.45-4.50

20. 85 + 2.45

23.30

Hope this helps ya!

5 0

2 years ago

Read 2 more answers

Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex

bagirrra123 [75]

Answer:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

$\hat p=0.021$ estimated proportion of interest

$p_o=0.012$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:

Null hypothesis: $p \leq 0.012$

Alternative hypothesis: $p > 0.012$

When we conduct a proportion test we need to use the z statisitic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0

3 years ago