Answer:
The answer is 18p^3r and 63p^3
Step-by-step explanation:
G.C.F of 18p^3 r and 45p^4q is = 9p^3
18p^3r = 2*3*3*p*p*p*r
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
G.C.F of 63p^3 and 45p^4q is = 9p^3
63p^3 = 3*3*7*p*p*p
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
Therefore the answer is 18p^3r and 63p^3....
Answer: 1/5, 1/2, 0.
Step-by-step explanation:
given data:
no of cameras = 6
no of cameras defective = 3
no of cameras selected = 2
Let p(t):=P(X=t)
p(2)=m/n,
m=binomial(3,2)=3!/2!= 3
n=binomial(6,2)=6!/2!/4! = 15
p(3)= 3/15
= 1/5.
p(1)=m/n,
m=binomial(6,1)*binomial(2,2)=6!/1!/4!*2!/2!/0!= 7.5
n=binomial(6,2)= 15
p(2)= 7.5/15
= 1/2
p(0)=m/n,
m=0
p(0)=0
Answer:
Options 2 and 6
Step-by-step explanation:
Those are the locations of the points on the graph. If you look closely, you will see that it counts by twos.
Answer:
Concurrent as my perception
