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Leto [7]
3 years ago
13

The formula for the circumference of a circle is c=2r,where r is the radios

Mathematics
1 answer:
Sedbober [7]3 years ago
6 0
PI x diameter squared
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Is 1/3+ 5 perpendicular
MrRa [10]

Answer:

yes 1/3 5 isb don't ehejdvduvrjdvdjrnrrjr didojdgovrodb

3 0
3 years ago
Read 2 more answers
15
Evgesh-ka [11]

Answer:

Height = 14.4

Step-by-step explanation:

The diagonals meet at right angles. Interesting property.

The hypotenuse is the side of the rhombus = 15 cm

One of the sides of the small triangles created by the intersection of the diagonals = 24/2 = 12

You can find the other side of the the triangle by using the Pythagorean Theorem

a^2 + b^2 = c^2

c = 15

a = 12

b = ?

12^2 + b^2 = 15^2

144 + b^2 = 225

b^2 = 225 - 144

b^2 = 81

b = 9

The area of this right angle = 9 * 12/2 = 54

There are 4 of them so 4 * 54 = 216

That's the area of the rhombus.

The h= Area / b

b = 15

h = 216/15

h = 14.4

8 0
2 years ago
Convert 5.100 × 10-3 to ordinary notation.<br> a.0.0005100<br> b.0.005100<br> c.510.0<br> d.5100
kondor19780726 [428]
5.100 x 10⁻³ = 5.100 x 0.001
                    = 0.005100      (shift the decimal point for 5 by 3 units left)

Alternatively, because 10⁻³ = 1/1000, therefore
5.100 x 10⁻³ = 5.1/1000

           0.0051
         ---------------
1000 | 5.100
           5000
           -------------
              1000
              1000
            
This yields the same result.

Answer: b. 0.005100
4 0
3 years ago
A 33 gram sample of a substance that's
Mazyrski [523]

9514 1404 393

Answer:

  6.2

Step-by-step explanation:

We presume your "k-value" is the k in the exponential decay term ...

  e^(-kt) . . . where t is the number of time units

This is 1/2 when ...

  ln(1/2) = -kt

  t = ln(1/2)/(-k) = ln(2)/k

  t = 0.69315/0.1124 ≈ 6.2

The half life is about 6.2 time units.

6 0
3 years ago
Rehana has some money after she spend Rs15 she has Three quarter of the initial amount left the amount left is
ludmilkaskok [199]

Answer:

Amount left = Rs 45

Step-by-step explanation:

Let the initial amount be x.

Translating the word problem into an algebraic expression, we have;

x - 15 = \frac {3}{4} * x

x - 15 = \frac {3x}{4}

Cross-multiplying, we have;

4(x - 15) = 3x

4x - 60 = 3x

Rearranging the equation (collecting like terms), we have;

4x - 3x = 60

x = Rs 60

Next, we find the amount left;

Amount left = 60 - 15

Amount left = Rs 45

6 0
3 years ago
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