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I am Lyosha [343]
3 years ago
13

Simplify where possible 3 (x+3)​

Mathematics
1 answer:
lawyer [7]3 years ago
8 0
Distributive property
3(x+3)

3*x + 3*3

3x+9

divide by three to simplify

x + 3

if you’re supposed to solve it, subtract three

x = -3
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Square root of 32 x square root of 1 over 18
lisov135 [29]
<h3>Solution:</h3>

\sqrt{32}  \times  \sqrt{ \frac{1}{18} }  \\  =  \sqrt{32}  \times  \frac{ \sqrt{1} }{ \sqrt{18} }  \\  =  \sqrt{32}  \times  \frac{1}{ \sqrt{18} }  \\  =  \frac{\sqrt{2 \times 2 \times 2 \times 2 \times 2}}{ \sqrt{2 \times 3 \times 3} }   \\  =  \frac{ \sqrt{ {2}^{2}  \times  {2}^{2}  \times 2} }{ \sqrt{2 \times  {3}^{2} } }  \\  =  \frac{2 \times 2 \times  \sqrt{2} }{3 \times  \sqrt{2} }  \\  =  \frac{4 \times  \sqrt{2} }{3 \times  \sqrt{2} }  \\  =  \frac{4}{3}

<h3>Answer:</h3>

\frac{4}{3}

<h3>Hope it helps...</h3>

ray4918 here to help

7 0
3 years ago
Select the number and name of the terms below (select 2): 2121
mihalych1998 [28]
Its a monomial and it has 4 terms
6 0
3 years ago
Numbers are numbers of the form...
Olenka [21]

Answer: Third option.

Step-by-step explanation:

In order to solve the given exercise it is important to remember that:

1. Rational numbers are defined as those numbers that can be wrriten as a  simple fraction.

2. The symbol for Rational numbers is: Q

3. Integers can be positive numbers, negative numbers and zero.

4. The symbol for Integers is: Z

5. Fractions have the following form:

\frac{a}{b}

Where:

 "a" is the numerator and "b" is the denominator.

The numerator "a" and the denominator "b" are both Integers ( and b\neq 0)

Therefore, based on the information given above, you can conclude that Rational numbers are numbers of the form \{\frac{a}{b}|a,b ∈ Z,b\neq0\}

4 0
3 years ago
What is the dilation ?
sammy [17]
I would personally have to say d it's not a or b though that's for sure
6 0
3 years ago
1/3 plus what number gives you 5/4
stira [4]

<u><em>The answer is 11/12.</em></u>

<u><em>I got the answer by subtracting 5/4-1/3 and the answer would be the answer to the problem.</em></u>

<u><em>Hope this helps!</em></u>

<u><em>:)</em></u>

8 0
3 years ago
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