Step-by-step explanation:
23. area of rect,r = 11 x 3.5 = 38.5cmsq
area of tri, t = 6 x3.5/2 = 10.5 cmsq
area of shaded region, sr = r-t
=> sr = 38.5- 10.5 = 28.5cmsq
24. area of square, s = 10x10 = 100mmsq
area of circle, c = pi x 5^2 = 78.5mmsq
area of shaded region, sr = s - c
=> sr = 100- 78.5 = 22.5mmsq
25. area of circle, c = pi x 6^2 = 113.04insq
area of tri, t = 6x12/2 = 36insq
area of shaded region, sr = c - t
=> sr = 113.04 - 36 = 77.04insq
What is the question asking?
The most simple form (I'm defining the parabola to be an upwards-opening one) would be
Answer:
The prize wheel diameter is 4.00 yards
Step-by-step explanation:
Area (A) = πd^2/4
πd^2 = 4A
d^2 = 4A/π
d (diameter) = √(4A/π)
A = 12.56 square yards, π = 3.142
d = √(4×12.56/3.142) = √15.99 = 4.00 yards
