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jenyasd209 [6]
3 years ago
15

Find two consecutive integers such that one fifth of the first less one-ninth of the second is 3. Pls answer.​

Mathematics
1 answer:
mart [117]3 years ago
4 0

Answer:

35 and 36

Step-by-step explanation:

To solve this problem, we must interpret it line by line;

  • We are dealing with consecutive integers; these are integers with a difference of 1 between them.

   let the first number = x

               second number  = x + 1

  • one - fifth of first;

             \frac{1}{5}x

  •   one - ninth of the second;

            \frac{1}{9}(x + 1)

for the "less" ;

         \frac{1}{5}x -  \frac{1}{9}(x + 1) = 3

Multiply through by 45

       45(\frac{1}{5}x) - (45) \frac{1}{9}(x + 1) = 3 x 45

           9x - 5(x + 1) = 135

           9x - 5x -5 = 135

             4x = 135 + 5

              4x = 140

                x = 35

Now, x+1  = 35 + 1 = 36

The consecutive integers are 35 and 36

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