Find two consecutive integers such that one fifth of the first less one-ninth of the second is 3. Pls answer.
1 answer:
Answer:
35 and 36
Step-by-step explanation:
To solve this problem, we must interpret it line by line;
- We are dealing with consecutive integers; these are integers with a difference of 1 between them.
let the first number = x
second number = x + 1
- one - fifth of first;
x
- one - ninth of the second;
(x + 1)
for the "less" ;
x -
(x + 1) = 3
Multiply through by 45
45(x) - (45)
(x + 1) = 3 x 45
9x - 5(x + 1) = 135
9x - 5x -5 = 135
4x = 135 + 5
4x = 140
x = 35
Now, x+1 = 35 + 1 = 36
The consecutive integers are 35 and 36
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