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2 years ago

14

Solve P= 2(L+W) for L

2 answers:

Law Incorporation [45]2 years ago

7 0

      P = 2(L + W)
      P = 2(L) + 2(W)
      P = 2L + 2W
P - 2W = 2L
    2    2
¹/₂P - W = L

Anna [14]2 years ago

5 0

Solve for l.
p=2(l+w)

Flip the equation.

2l+2w=p

Add -2w to both sides.

2l+2w+−2w=p+−2w

2l=p−2w

Divide both sides by 2.

2l/2=p−2w/2

l=1/2p−w

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Natasha2012 [34]

The answer the 3,

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2 years ago

How to write 6.716 im fraction

Varvara68 [4.7K]

Answer:

To write 6.716 as a fraction you have to write 6.716 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

6.716 = 6.716/1 = 67.16/10 = 671.6/100 = 6716/1000

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2 years ago

Find the missing value so that the two points have a slope of -2.(1,y) and (6,-5)

Aloiza [94]

Answer:

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3 years ago

Hey guys! Can you simplify this? Be sure to show your work so i know you aren't guessing! Also remember when you answer a questi

Svetlanka [38]

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5 0

2 years ago

Which statement is true?

love history [14]

<h2>Hello!</h2>

The answer is:

The second option,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

<h2>Why?</h2>

Discarding each given option in order to find the correct one, we have:

<h2>First option,</h2>

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[2m]{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[m]{xy}$

<h2>Second option,</h2>

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

The statement is true, we can prove it by using the following properties of exponents:

$(a^{b})^{c}=a^{bc}$

$\sqrt[n]{x^{m} }=x^{\frac{m}{n} }$

We are given the expression:

$(\sqrt[m]{x^{a} } )^{b}$

So, applying the properties, we have:

$(\sqrt[m]{x^{a} } )^{b}=(x^{\frac{a}{m}})^{b}=x^{\frac{ab}{m}}\\\\x^{\frac{ab}{m}}=\sqrt[m]{x^{ab} }$

Hence,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

<h2>Third option,</h2>

$a\sqrt[n]{x}+b\sqrt[n]{x}=ab\sqrt[n]{x}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$a\sqrt[n]{x}+b\sqrt[n]{x}=(a+b)\sqrt[n]{x}$

<h2>Fourth option,</h2>

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=m\sqrt{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=\sqrt[m]{\frac{x}{y} }$

Hence, the answer is, the statement that is true is the second statement:

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

Have a nice day!

6 0

2 years ago