Answer:
4
Step-by-step explanation:
Step 1: find (r- s) or r(x) - s(x)
r(x) - s(x) = 3x - 1 - (2x + 1)
r(x) - s(x) = 3x - 1 - 2x - 1 (distribute the -1 to 2x and 1)
r(x) - s(x) = x - 2 (combine like terms, 3x + (-2x) = x, -1 + (-1) = -2)
so r(x) - s(x) = x - 2, or (r - s)(x) = x - 2
Step 2: Plug in 6 to 'x' and find (r - s)(x)
(r - s)(6) = 6 - 2 = 4
hain hai ka hai ka bhi ka ke hai khaie hai ka hai
Answer:
no solution
Step-by-step explanation:
a solution would mean a point where the two lines cross. theres no such thing for parallel lines.
but if the lines are the same, they are parallel and cross everywhere, that would give infinite solutions.
if they would cross once, it would mean one solution
Answer:
the answer is C - no association
Take into account, that in general, a cosine function of amplitude A, period T and vertical translation b, can be written as follow:
In the given case, you have:
A = 4
T = 3π/4
b = -3
By replacing you obtain:
Hence, the answer is:
f(x) = 4cos(8/3 x) - 3
