Answer:
[0, infinity)
Step-by-step explanation:
A square root can only use positive numbers, otherwise it becomes imaginary. A function needs to be real to output real values. Therefore, the domain is everything from 0 onwards.
The answer to your question is -10
x=6
3x-5=2x+1
x-5=1
-1/3 a + 4 ≤ 0
3*(-1/3a) + 4*3 ≤ 0*3
-a + 12 ≤ 0
12 ≤ a
12 ⩾a
a⩾12
