N; n+1; n+2 - 3 consecutive numbers
n(n + 1) = (n + 2)² - 19 |use a(b + c) = ab + ac and (a + b)² = a² + 2ab + b²
n² + n = n² + 4n + 4 - 19 |subtract n² from both sides
n = 4n - 15 |subtract 4n from both sides
-3n = -15 |divide both sides by (-3)
n = 5
n + 1 = 5 + 1 = 6
n + 2 = 5 + 2 = 7
Answer: 5; 6; 7.
The answer would be (2,3).
Try sketching it out, it helps :)
Answer:
Step-by-step explanation:
The intersection is when both functions have same coordinates
Substitute to get
- - 2x + 16 = 4x + 10
- 4x + 2x = 16 - 10
- 6x = 6
- x = 1
The y- coordinate is
- y = - 2(1) + 16 = -2 + 16 = 14
So the intersection point is (1, 14)
x^2 - 9 = (x + 3)(x -3)
3x - 9 = 3(x - 3)
and
6
Common denominator would be 6(x+3)(x - 3)
Answer: 6(x+3)(x - 3)
