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AysviL [449]
2 years ago
5

Help please I don’t know

Mathematics
1 answer:
RideAnS [48]2 years ago
8 0
Im pretty sure that means what is y when x is -5. the answer is 5
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When solving a system of equations, Jared found y = x + 10 for one equation and substituted x + 10 for y in the other equation.
myrzilka [38]
Both are correct they just chose a different variable to solve for first. they will both get correct answers if they do the rest correctly.
5 0
3 years ago
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Two consecutive odd integers whose sum is 76.
ollegr [7]

Answer:

37 and 39

Step-by-step explanation:

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How do you write 1/2 as a decimal
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3 0
3 years ago
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Jerry charges $15 for each lawn that he cuts. Depending homework and chores, he has time to cut at most 10 lawns a week. Jerry h
vova2212 [387]

Answer:  D) Number of yards Jerry cuts; 0 ≤ x ≤ 10  

Step-by-step explanation:

Here the given function that describes the total profit,

y = 15 x - 10

Where x represents the number of lawns Jerry cut in a week.

But, Depending homework and chores, he has time to cut at most 10 lawns a week.

Thus, x ≤ 10

Also, the number of lawns can not be negative.

Therefore, x ≥ 0

And, the value of x will decide the domain of the function y,

Thus, the domain of the given function is,

0 ≤ x ≤ 10

⇒ Option D is correct.



6 0
3 years ago
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If lim x-> infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b
MAXImum [283]

We have

\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}

So

\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0

The rational term vanishes as <em>x</em> gets arbitrarily large, so we can ignore that term, leaving us with

\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0

and this happens if <em>a</em> = 1 and <em>b</em> = -1.

To confirm, we have

\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-x+1\right)=\lim_{x\to\infty}\frac{x^2-(x-1)(x+1)}{x+1}=\lim_{x\to\infty}\frac1{x+1}=0

as required.

3 0
3 years ago
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