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lawyer [7]
3 years ago
15

How do I establish this identity??

Mathematics
1 answer:
Aloiza [94]3 years ago
8 0
\frac{cosec\theta+cotan\theta} {sec\theta+tan\theta}=\frac{cosec\theta+cotan\theta} {sec\theta+tan\theta}\times\frac{cosec\theta-cotan\theta}{cosec\theta-cotan\theta}\times\frac{sec\theta-tan\theta} {sec\theta-tan\theta}

And use that,

\sec^2\theta-\tan^2\theta=1

cosec^2\theta-cotan^2\theta=1
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Express the integral as an iterated integral in six different ways, where E is the solid bounded by y=4-x^2-4z^2 and y=0
zmey [24]
Assuming you need the integral expressing the volume of E, the easiest setup is to integrate with respect to y first.

This is done with either

\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_{-2}^2\int_0^{4-x^2-z^2}\mathrm dy\,\mathrm dx\,\mathrm dz
\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_{-2}^2\int_0^{4-x^2-z^2}\mathrm dy\,\mathrm dz\,\mathrm dx

Thanks to symmetry, integrating with respect to either x or z first will be nearly identical.

First, with respect to x:

\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_0^4\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-z^2}}\mathrm dx\,\mathrm dy\,\mathrm dz
\displaystyle\iiint_E\mathrm dV=\int_0^4\int_{-2}^2\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-z^2}}\mathrm dx\,\mathrm dz\,\mathrm dy

Next, with respec to z:

\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_0^4\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-x^2}}\mathrm dz\,\mathrm dy\,\mathrm dx
\displaystyle\iiint_E\mathrm dV=\int_0^4\int_{-2}^2\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-x^2}}\mathrm dz\,\mathrm dx\,\mathrm dy
5 0
3 years ago
Kaitlyn was asked to find which expression below is equivalent to -3x + 5(x + 2)?
NISA [10]
The correct answer is c (2x+10)
I think her error was that she multiplied he numbers wrong
4 0
3 years ago
Read 2 more answers
Which measure is usually the least useful in describing the data for a stem-and-leaf plot? range median mode mean
FromTheMoon [43]

Answer:

Mean: For this case would be not useful since in the stem leaf plot is difficult to find this measure with this chart

Step-by-step explanation:

We want construct a stem and leaf plot and we want to find the measure least useful.

And for this case if we analyze the option we have:

Range: That very useful and it can be extracted from the stem and leaf plot

Median: It could be easy to find it with the stem leaf plot

Mode: With a stem leaf plot we can find easily the most repeated value

Mean: For this case would be not useful since in the stem leaf plot is difficult to find this measure with this chart

3 0
3 years ago
Please help me I can’t figure out how to solve
kirza4 [7]
I don’t know how to do it,, but use photomath, it’s perfect for these type of questions
8 0
3 years ago
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What is the area of the figure? Please help!
makvit [3.9K]
First brake the figure into 3 rectangles . One across and 2 going up and down . Then solve for the small figures and add up all the areas together . Hope this helps . 
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3 years ago
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