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lawyer [7]
3 years ago
15

How do I establish this identity??

Mathematics
1 answer:
Aloiza [94]3 years ago
8 0
\frac{cosec\theta+cotan\theta} {sec\theta+tan\theta}=\frac{cosec\theta+cotan\theta} {sec\theta+tan\theta}\times\frac{cosec\theta-cotan\theta}{cosec\theta-cotan\theta}\times\frac{sec\theta-tan\theta} {sec\theta-tan\theta}

And use that,

\sec^2\theta-\tan^2\theta=1

cosec^2\theta-cotan^2\theta=1
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