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lesya692 [45]
3 years ago
13

What is the axis of symmetry

Mathematics
1 answer:
Verdich [7]3 years ago
5 0

Answer:

its is x=0

Step-by-step explanation:

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Brett is making a fruit salad. The recipe calls for 1 1 2 cups of apple, 3 4 cup of oranges, and 2 3 cup of grapes. How many cup
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I believe he made 169 cups of fruit salad, or is it a trick question?
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4 years ago
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A crane is lowering a concrete block from a height of 270 feet above the ground at a constant rate of 2.5 feet per second. Which
iogann1982 [59]

The function would be h = 270 - 2.5s, where h is the height (in feet) and s it the time (in seconds) that has passed.

The 270 represents the initial value, which is given. We are told that the initial height of the block is 270 feet.

2.5s represents the feet that it has descended. We know the block is lowered at a rate of 2.5 feet per second. Multiplying this by s, the time, will give us how much it has descended.

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3 years ago
What is tan(x) equal to?<br> 1<br> 2<br> sin(x)<br> cos(x)<br> sin(x)/cos(x)
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Answer: sin(x) / cos(x)

Step-by-step explanation: This is just a trigonometric identity you should have memorized :)

8 0
3 years ago
104/5.1 rounded to the nearest tenth
matrenka [14]

Answer:

20.4

Step-by-step explanation:

104 ÷ 5.1 = 20.3921

20.3<u>9</u> = 20.4

4 0
3 years ago
Suppose that the length of a phone call in minutes is an exponential random variable with parameter λ = 1/ 8. If someone arrives
Elis [28]

Answer:

a) P=0.535

b) P=0.204

c) P=0.286

Step-by-step explanation:

The exponential distribution is expressed as

F(x>t)=e^{-\lambda t}

In this example, λ=1/8=0.125 min⁻¹.

a) The probability of having to wait more than 5 minutes

F(x>5)=e^{-0.125*5}=e^{-0.625}=0.535

b) The probability of having to wait between 10 and 20 minutes

F(1020)=e^{-0.125*10}-e^{-0.125*20}\\\\F(10

c) The exponential distribution is memory-less, so it is independent of past events.

If you have waited 5 minutes, the probability of waiting more than 15 minutes in total is the same as the probability of waiting 15-5=10 minutes.

F(x>15|t^*=5)=F(x>15)/F(x>5)=\frac{e^{-0.125*15}}{e^{-0.125*5}}=e^{-0.125*(15-5)}\\\\ F(x>15|t^*=5)=e^{-0.125*(10)}=F(x>10)=0.286

5 0
3 years ago
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