You have to plug in 2 for a and 6 for b.
(2)^2 + 4(2) + 7(6) 4 + 8 + 42 54
————————— = —————- = ——
5 - (2)^3 5 - 8 -3
The answer is -18.
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Answer:
Step-by-step explanation:
We know the rhombus has perpendicular diagonals and the diagonals bisect each other.
The diagonals are AD and BC.
- <em>Note. The points C and D should have swapped coordinates. This becomes ABDC.</em>
<u>The midpoint of BC is:</u>
- ([3 + 2]/2,[4 + 1]/2) = (2.5, 2.5)
<u>Use A(x, y) and midpoint formula for the other diagonal AD:</u>
- (x + 4)/2 = 2.5 ⇒ x + 4 = 5 ⇒ x = 1
- (y + 2)/2 = 2.5 ⇒ y + 2 = 5 ⇒ y = 3
Point A has coordinates (1, 3)
Correct choice is B
See the picture
Step-by-step explanation:
kindly find attached detailed information of the remaining information as requested for your reference
1. The lower class limit is the left number in the age column
i.e in the 25-34 the lower class limit is 25
2. The upper class limit is the right number in the age column
i.e in the 25-34 the lower class limit is 34
3. The class width is the difference between the class boundaries of a single class
class width = 34.5-24.5= 10
4. The number of individuals is= 29+34+16+3+5+1+2= 90