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Savatey [412]
3 years ago
14

How many solutions does the following equation have? -5(2+1) = –22 + 10

Mathematics
1 answer:
Igoryamba3 years ago
7 0

Answer:

0 real # solution

Step-by-step explanation:

b^2-4ac<1 is equal to 0 real number solution and

-5(2+1)=-22+10

-5(2+1)=-12

which is less than 1

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PLEASE HELP ME!! 12 points and brainliest!!!!!!
Darina [25.2K]
What you want to do is get x alone. So, divide both sides by -1/2 so x is alone. -12 divided by -1/2 is 24. Since this is an  inequality you have to flip over your inequality sign when multiplying or dividing by a negative so your answer is now x>24

6 0
3 years ago
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How many times does 81,000 goes into 8,000
Effectus [21]
Zero. That number cannot go into that one
8 0
3 years ago
If a polynomial function f(x) has roots -8, 1, and 6i, what must also be a root of f(x)?
Naddik [55]

Answer:

it must also have the root : - 6i

Step-by-step explanation:

If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.

This is because in order to render a polynomial with Real coefficients, the binomial factor  (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:

(x-(a+bi))*(x-(a-bi))=\\(x-a-bi)*(x-a+bi)=\\([x-a]-bi)*([x-a]+bi)=\\(x-a)^2-(bi)^2=\\(x-a)^2-b^2(-1)=\\(x-a)^2+b^2

where the imaginary unit has disappeared, making the expression real.

So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)

Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.

5 0
3 years ago
Name the Solid.
Soloha48 [4]

Answer:

Pyramid

V= 240 m^3

Step-by-step explanation:

The volume of a pyramid is 1/3 the Base times the height.

1/3x(10x8)x9

7 0
2 years ago
What is the effect on the area of a rectangle if the dimensions are doubled?
alisha [4.7K]
Let x be the length and y be the width of a rectangle.
Area = xy

When x and y are doubled
Length = 2x and Width = 2y
Area = 2x x 2y
Area = 4xy

-------------------------------------------------------------------------------------------------
Answer: When the dimension is doubled, the area is 4 times the original.
-------------------------------------------------------------------------------------------------
8 0
3 years ago
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