Answer:
The points which satisfy the given lines is ( 1 , 1 )
Step-by-step explanation:
Given as :
The equation of lines is
y = 3 x - 2 ........ 1 And
y = - 2 x + 3 ........ 2
From equation given
3 x - 2 = - 2 x + 3
Or , 3 x + 2 x = 3 +2
Or, 5 x = 5
So , x =
= 1
Put the value of x in eq 1
So, y = 3 ( 1 ) - 2
Or, y = 3 - 2 = 1
∴, the points ( x , y ) = ( 1 , 1 )
Hence The points which satisfy the given lines is ( 1 , 1 ) Answer
Answer:
1
Step-by-step explanation:
First find f(0) and g(0). These are the values where x=0 in each function.
f(0) = 1+0 = 1
g(0) = 1^2 - 1 = 1-1 = 0
So f(0) = 1 and g(0) = 0.
Now substitute f(0) = 1 into g(t).
g(1) = 1^2 -1 = 1-1 = 0.
So g(f(0)) = 0.
Now substitute g(0) = 0 into f(t).
f(0) = 1 + 0 = 1.
So f(g(0)) = 1.
Add the values 0 and 1 to get 0+1 = 1.
Answer:
im sorry, the answer to what?