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Tanzania [10]
3 years ago
13

An athletics coach states that the distribution of player run times (in seconds) for a 100-meter dash is normally distributed wi

th a mean equal to 13.00 and a standard deviation equal to 0.2 seconds. What percentage of players on the team run the 100-meter dash in 13.28 seconds or faster
Mathematics
1 answer:
Elza [17]3 years ago
8 0

Answer:

P(X

And we can find this probability using the normal standard distribution table and we got:

P(z

And the percentage faster than 13.28 seconds would be 91.9%

Step-by-step explanation:

Let X the random variable that represent the runtimes of a population, and for this case we know the distribution for X is given by:

X \sim N(13,0.2)  

Where \mu=13 and \sigma=0.2

We want to find this probability:

P(X

And we can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

Using this formula we have:

P(X

And we can find this probability using the normal standard distribution table and we got:

P(z

And the percentage faster than 13.28 seconds would be 91.9%

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\begin{array}{l}{\text { diameter }=2 \times \text { radius } \rightarrow \text { radius }=\frac{\text {diameter}}{2}} \\\\ {\rightarrow \text { radius }=\frac{16}{2} \rightarrow \text { radius }=8 \text { kilometers. }}\end{array}

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