The x axis is the horizontal flat axis (think of it as the ground). Reflect triangle A over this horizontal line and you end up with triangle C. The same can be said in reverse from C to A.

7 0

3 years ago

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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B6y%2B7%7D%3D5%2B%5Csqrt%7By-3%7D%20%5C%5CI%20get%20how%20to%20begin%20this%20but%20h

PilotLPTM [1.2K]

Answer:

$\sqrt{6y+7} -\sqrt{y-3} =5\\(\sqrt{6y+7} -\sqrt{y-3} )^2=5^2\\\sqrt{6y+7} ^2+\sqrt{y-3} ^2-2\sqrt{(6y+7)(y-3)} =25\\6y+7+y-3-25=2\sqrt{(6y+7)(y-3)} \\7y-21=2\sqrt{(6y+7)(y-3)} \\(7y-21)^2=(2\sqrt{6y^2-18y+7y-21} )^2\\49y^2+441-294y=4(6y^2-11y-21)\\49y^2+441-294y=24y^2-44y-84\\49y^2-24y^2+441+84-294y+44y=0\\25y^2-250y+525=0\\25(y^2-10y+21)=0\\y^2-10y+21=0\\y^2-7y-3y+21=0\\y(y-7)-3(y-7)=0\\(y-7)(y-3)=0\\y-7=0 or y-3=0\\y=7 ,y=3$

Step-by-step explanation:

8 0

3 years ago

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There is a bag with only milk and dark chocolates, the probability of randomly choosing a dark chocolate is 7/9, there are 21 da

amid [387]

Answer:

6 milk chocolates

Step-by-step explanation:

7/9=21

21/7=3

3=1/9

3*9=27

27=total chocolates

21=dark chocolates

27-21=6

4 0

3 years ago

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Given: ∆PQR, m∠R = 90° m∠PQR = 75°, m∠MQR = 60° M ∈ PR , MP = 18 Find: RQ

Darina [25.2K]

Answer:

RQ = 9.

Step-by-step explanation:

m < RPQ = 180 - 90 - 75 = 15 degrees

m < PQM = 75 - 60 = 15 degrees.

So triangle PMQ is isosceles so side PM is congruent to side MQ, therefore MQ = 18.

Triangle RQM is a 30-60-90 triangle with RQ the shortest leg (because it is opposite the lowest angle) so that makes RQ = 1/2 of MQ. (The sides in a 30-60-90 triangle are in the ratio 1:sqrt3:2)

RQ = 1/2 * 18 = 9.

6 0

3 years ago