Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
To determine the correct answer, you will need to find the ranges, means, medians, and mode of City B. You can compare the answers then to answer the question. Please see the attached picture for the necessary information.
The correct choice is the first statement about the mode for City B.
Answer:
-132
Step-by-step explanation:
x/12 = -11
<u>⋅ 12 = ⋅ 12</u>
x = -132
Step-by-step explanation:
x -0.1x = x(1-0.1) = 0.9x
<span>Pythagorean triple
a^2 + b^2 = c^2
so
5^2 + 12^2 = 13^2
25 + 144 = 169
169 = 169
answer is D. last one 5, 12 , 13</span>
