We are given dimensions of the snacks box:
Length = 2 1/2 inches.
Width = 1 1/2 inches and
Height = 4 inches.
Volume of the box formula:
V = Length × width × height
V = 2 1/2 × 1 1/2 ×4
=
<h3>Therefore, the volume of this Hamsta' snacks box is 15 inches cube.</h3>
Answer:
4
Step-by-step explanation:
In a rhombus, the diagonals are congruent. It is not always true. If the diagonals become congruent then It becomes square. Hope this helps!
Answer: 306in^3
method: I would split the cross-section (the trapezium at the front) into two shapes. You first have your rectangle with dimensions of 4 and 7, and your triangle with dimensions of height 4 and base 3 (10 - 7 = 3). 4 × 7 = 28in^2, 4 × 3 = 12, 12 ÷ 2 = 6in^2. The total surface area of the cross-section is therefore 6 + 28 = 34in^2. Now, to find the volume, you just multiply that by 9 which is 306in^3, which is your answer. I hope this helps!
It will be a circle with a center of (3, -4) and a radius of 12.
Solution :
It is given that :
Casey boarded a Ferry wheel at position of 3 'o' clock.
The angular speed of the Ferry wheel = 5.6 radians per minute
The radius of the Ferry wheel = 50 feet
The height of the center wheel of the Ferry from the ground = 55 feet
Let the number of minutes be = t
a). The expression of the varying number of radians θ is given by :
After t minutes, θ = angle swept
θ = 5.6 t radians
b). Finding the height from the center of the wheel.
We know that : y = r sin θ
Given r = 50 feet
So, y = 50 sin (5.6 t) feet
Therefore, the height above the ground can be found by :
h = y + 55 (from ground)
h = 50 sin (5.6 t) + 55 feet
