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FinnZ [79.3K]
3 years ago
14

Which transformation is happening in the image below​

Mathematics
1 answer:
s2008m [1.1K]3 years ago
8 0

Answer:

B.) Reflection over y=-3

Step-by-step explanation:

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Statement 1: A closed figure is a regular octagon if and only if it has exactly 8 congruent sides.
TEA [102]

Answer:

statement 2 is the inverse of statement 1

5 0
2 years ago
Angie is making wreaths to sell at a craft show. She has 6.5 yards of ribbon. Each wreath has a bow made from 1 1/3 yards of rib
Elodia [21]
Angie has a total of 6.5 yards of ribbon. Her goal is to take advantage over it by making a wreath. Each wreath has length of 1 1/3 yards.
In order for us to know how many wreath will be made, we'll divide the fraction to the total length of the ribbon.

= 6.5 / 1 1/3
= 6 1/2 / 4/3
= 13/2  * 3/4
= 39 / 8
= 4.875

So, there are 4 bows or wreath can be made.
7 0
3 years ago
Let X1, . . . ,Xn be an i.i.d. random sample from a N(0, 1) population. Define Y1 = 1 n n X i=1 Xi , Y2 = 1 n n X i=1 |Xi| . Cal
nalin [4]

For each 1\le i\le n, E[X_i]=0, so that

\displaystyle E[Y_1]=E\left[\frac1n\sum_{i=1}^nX_i\right]=\frac1n\sum_{i=1}^nE[X_i]=0

Meanwhile,

\displaystyle E[Y_2]=\frac1n\sum_{i=1}^nE[|X_i|]

Each of the X_i have PDF

f_{X_i}(x)=\dfrac1{\sqrt{2\pi}}e^{-x^2/2}

for x\in\Bbb R. From this we get

E[|X_i|]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty|x|e^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}\int_0^\infty xe^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}

\implies E[Y_2]=n\sqrt{\dfrac2\pi}

8 0
2 years ago
Help me please I need
vagabundo [1.1K]

Answer:

I think the answer is A=49

8 0
3 years ago
What number added to 2 leaves 3 less than 3/5 of 10
inysia [295]
X + 2 = 3/5(10) - 3
x + 2 = 6 - 3
x + 2 = 3
x = 3 - 2
x = 1 <=== ur number
7 0
3 years ago
Read 2 more answers
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