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Marat540 [252]
3 years ago
8

547% of what number is 366.49

Mathematics
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

67

Step-by-step explanation:

To solve this question ( that is to know the number), we must interpret the statement mathematically. Let the unknown number be T then,

547% of T = 366.49

547 * T/100 = 366.49

547T = 36646

T = 36649/547

= 67

It means that 547% of 67 gives 366.49

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geniusboy [140]

Answer:

$25.30

Step-by-step explanation:

15% of 22 = 3.3

22 + 3.3 = 25.30

7 0
3 years ago
Choose the correct simplification of the expression (2x2y6z5)(5x4y5z3).
erastovalidia [21]

Answer:

The correct option is 4.

Step-by-step explanation:

The given expression is

(2x^2y^6z^5)(5x^4y^5z^3)

Simplify the given expression.

(2x^2y^6z^5)\times (5x^4y^5z^3)

(2\times 5)(x^2x^4)(y^6y^5)(z^5z^3)

10x^{2+4}y^{6+5}z^{5+3}                  [\because x^mx^n=x^{m+n}]

10x^6y^{11}z^8

Therefore correct option is 4.

8 0
3 years ago
Find the discriminant of 3x2 - 10x=-2.
FrozenT [24]

Answer:

x= 4/5 or 0.8

Step-by-step explanation:

7 0
3 years ago
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A football team started at the line of scrimmage. On the first play of the drive, the team lost 4 yards. On the second play of t
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It’s supposed to be -4+45=41
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Consider a uniform distribution from aequals4 to bequals29. ​(a) Find the probability that x lies between 7 and 27. ​(b) Find th
weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

P(c \leq x \leq d) = \frac{d - c}{b - a}

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So c = 7, d = 27

P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8

80% probability that x lies between 7 and 27.

​(b) Find the probability that x lies between 6 and 13. ​

So c = 6, d = 13

P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

​So c = 9, d = 20

P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So c = 11, d = 18

P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28

28% probability that x lies between 11 and 18.

3 0
3 years ago
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