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marishachu [46]
3 years ago
6

1. Choose the answer that correctly expresses this ratio in fraction form.

Mathematics
1 answer:
Alborosie3 years ago
8 0

divide each number by 18

2:3


2/3



number 2:


25/50  divide each by 25


1/2


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Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
Artemon [7]

Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)

By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

6 0
3 years ago
#8 please. GCF of 117, 99, and 126
Advocard [28]
The factors of 117 are: 1, 3, 9, 13, 39, and 117
The factors of 99 are: 1, 3, 9, 11, 33, and 99 
The factors of 126 are: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, and 126

The greatest common factors of 117, 99, and 126 are: 1, 3, and 9. And according to your answer choices your answer is C. 9
7 0
2 years ago
Solve for n: 21 K - 3n + 9 p is greater than 3 p + 12
Digiron [165]

Answer:

n > p + 1 + 7k

Step-by-step explanation:

21k - 3n + 9 > 3p + 12

21k - 3n > 3p + 12 - 9

3n > 3p + 3

3n > 3p + 3 + 21k

n > (3p + 3 + 21k)/3

n > p + 1 + 7k

6 0
3 years ago
If vector A⃗ has components Ax and Ay and makes an angle θ with the +x axis, then...
Lesechka [4]
If vector A⃗ has components Ax and Ay and makes an angle θ with the +x axis, then tanθ = Ay/Ax to get the angle of the vector components. Since the trigonometric function of tanθ is sinθ over cosθ, and since sinθ = y/r and cosθ = x/r.
7 0
2 years ago
I don't get how to solve for x with prathesis
Brums [2.3K]
Just remember that something outside the parentheses applies to everything inside.

Examples:

3 times (x + 2) . . . . . means . . . . . 3 times 'x'  <u>plus</u>  3 times 2

a (b + c) . . . . . means . . . . . ab  <u>plus</u>  ac

4 (w + x + y + 2) . . . means . . . 4w + 4x + 4y + 8

When somebody gives you an equation that has parentheses in it,
the first thing you're always supposed to do is get rid of them. 
With the examples I just gave you, you know how to do that now.


5 0
3 years ago
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