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3 years ago

Simplify the expression

2 answers:

7 0

2x+3(x-2)-3(x-6) You would first distribute. So: 2x+3x-6-3x+18 Then you would combine like terms, like so: 2x+3x-3x= 2x -6+18= 12 So it'd be: 2x + 12 Which is answer choice A HOPE THIS HELPS!!(:

borishaifa [10]3 years ago

5 0

$2x+3(x-2)-3(x-6) \\ \\ 2x + 3x - 6 - 3x + 18 \ / \ expand \\ \\ (2x + 3x - 3x) - 6 + 18 \ / \ gather \ the \ like \ terms \\ \\ 2x - 6 + 18 \ / \ simplify \\ \\ 2x + 12 \ / \ simplify \\ \\$

The final result is A) 2x + 12.

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kim owes $870.00 on her mastercard account. She returns two items costing $35.90 and $150.00 and receive credits for these on th

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Answer:

She has 499.3$

Step-by-step explanation:

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3 years ago

Plllsss help!!! <br>What is the value of x?

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Step-by-step explanation:

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2 years ago

Read 2 more answers

What is the answer to x/3 - 2 < 8

balu736 [363]

Step-by-step explanation:

$\frac{x}{3} - 2 < 8 \\ \frac{x}{3} < 10 \\ x < 30$

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2 years ago

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yKpoI14uk [10]

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Step-by-step explanation:

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2 years ago

Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

8 0

3 years ago