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2 years ago

Which is the formula for slope of a line.

Mathematics

2 answers:

PilotLPTM [1.2K]2 years ago

4 0

If the line passes through the points $A(x_1,y_1)$ and $B(x_2,y_2),$ then the slope of the line can be determined as

$m=\dfrac{y_2-y_1}{x_2-x_1}.$

Then the equation of the line is

$y=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)+y_1.$

Answer: correct choice is B

In-s [12.5K]2 years ago

3 0

<u>Answer:</u>

The correct answer option is $m=\frac{y_2-y_1}{x_2-x_1}$ .

<u>Step-by-step explanation:</u>

To the find of the slope of a line, we need at least two points that are on the line: $(x1,y_1)$ and $(y_1,y_2)$ .

With the help of the coordinates of these two points, we can find the slope of the line by taking the ratio of the difference in values of y by the difference in values of x.

The slope of a line is denoted by $m$ :

$m=\frac{y_2-y_1}{x_2-x_1}$

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Answer:

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8^2+15^2=20^2

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andreyandreev [35.5K]

First expression: (-7)/(-4)

Divide. Note that two negative numbers divided will result in a positive answer

(-7)/(-4) = 7/4 = 1.75

First expression: Greater than 1.

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Second expression: -(3/2)

Simplify: 3/2 = 1.5

-(1.5) = -1.5

Second expression: Less than -1

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Third expression: (-8/5) x (-5/8)

Note that two negatives = one positive answer when multiplying

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Fourth Expression: (-5)/(-3)

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Read 2 more answers

MCR3U1 Culminating 2021.pdf

11111nata11111 [884]

Answer:

(a) $y = 350,000 \times (1 + 0.07132)^t$

(b) (i) The population after 8 hours is 607,325

(ii) The population after 24 hours is 1,828,643

(d) The doubling time of the population is approximately, 10.06 hours

Step-by-step explanation:

(a) The initial population of the bacteria, y₁ = a = 350,000

The time the colony grows, t = 12 hours

The final population of bacteria in the colony, y₂ = 800,000

The exponential growth model, can be written as follows;

$y = a \cdot (1 + r)^t$

Plugging in the values, we get;

$800,000 = 350,000 \times (1 + r)^{12}$

Therefore;

(1 + r)¹² = 800,000/350,000 = 16/7

12·㏑(1 + r) = ㏑(16/7)

㏑(1 + r) = (㏑(16/7))/12

r = e^((㏑(16/7))/12) - 1 ≈ 0.07132

The model is therefore;

$y = 350,000 \times (1 + 0.07132)^t$

(b) (i) The population after 8 hours is given as follows;

y = 350,000 × (1 + 0.07132)⁸ ≈ 607,325.82

By rounding down, we have;

The population after 8 hours, y = 607,325

(ii) The population after 24 hours is given as follows;

y = 350,000 × (1 + 0.07132)²⁴ ≈ 1,828,643.92571

By rounding down, we have;

The population after 24 hours, y = 1,828,643

∴ The rate of increase of the population as a percentage = 0.07132 × 100 = 7.132%

(d) The doubling time of the population is the time it takes the population to double, which is given as follows;

Initial population = y

Final population = 2·y

The doubling time of the population is therefore;

$2 \cdot y = y \times (1 + 0.07132)^t$

Therefore, we have;

2·y/y =2 = $(1 + 0.07132)^t$

t = ln2/(ln(1 + 0.07132)) ≈ 10.06

The doubling time of the population is approximately, 10.06 hours.

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