Answer:
3. 8y= -7x -12
4. -3y= 4x -12
5. 7y= -2x +4
Do you want me to do the rest?
did you got it??
The rest are:
6. -3y =6x +12
7. -10y= 5x+20
8. 4y=2x +12
Answer:
3.50 cups
Step-by-step explanation:
6-2.25=4.75
4.75-1.25=3.50
Answer:
a) <u>0.4647</u>
b) <u>24.6 secs</u>
Step-by-step explanation:
Let T be interval between two successive barges
t(t) = λe^λt where t > 0
The mean of the exponential
E(T) = 1/λ
E(T) = 8
1/λ = 8
λ = 1/8
∴ t(t) = 1/8×e^-t/8 [ t > 0]
Now the probability we need
p[T<5] = ₀∫⁵ t(t) dt
=₀∫⁵ 1/8×e^-t/8 dt
= 1/8 ₀∫⁵ e^-t/8 dt
= 1/8 [ (e^-t/8) / -1/8 ]₀⁵
= - [ e^-t/8]₀⁵
= - [ e^-5/8 - 1 ]
= 1 - e^-5/8 = <u>0.4647</u>
Therefore the probability that the time interval between two successive barges is less than 5 minutes is <u>0.4647</u>
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b)
Now we find t such that;
p[T>t] = 0.95
so
t_∫¹⁰ t(x) dx = 0.95
t_∫¹⁰ 1/8×e^-x/8 = 0.95
1/8 t_∫¹⁰ e^-x/8 dx = 0.95
1/8 [( e^-x/8 ) / - 1/8 ]¹⁰_t = 0.95
- [ e^-x/8]¹⁰_t = 0.96
- [ 0 - e^-t/8 ] = 0.95
e^-t/8 = 0.95
take log of both sides
log (e^-t/8) = log (0.95)
-t/8 = In(0.95)
-t/8 = -0.0513
t = 8 × 0.0513
t = 0.4104 (min)
so we convert to seconds
t = 0.4104 × 60
t = <u>24.6 secs</u>
Therefore the time interval t such that we can be 95% sure that the time interval between two successive barges will be greater than t is <u>24.6 secs</u>
Their family drove 7,305 miles that year. Hope this helps!!
Answer:
Step-by-step explanation:
From the given picture,
Given : l₁ and l₂ are the parallel lines and ∠2 ≅ ∠4
To prove: ∠1 ≅ ∠4 and ∠4 ≅ ∠3
Statements Reasons
1). l₁ ║ l₂ and ∠2 ≅ ∠4 1). Given
2). ∠1 ≅ ∠2 2). Vertical angle theorem
3). ∠1 ≅ ∠4 3). Given
4). ∠1 ≅ ∠3 4). Corresponding angle theorem
5). ∠4 ≅ ∠3 5). Transitive property of congruence
