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maw [93]
3 years ago
12

Please help me! Will give brainleist! ✨

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
7 0

Answer:

1/16

Step-by-step explanation:

Multiply top with top and bottom with bottom

1/8 * 3/6 = (1*3)/(8*6) = 3/48

3 goes into 48

16 times

The answer is 1/16

The correct answer is 1/16 even though 3/48 is also correct. The question directions you to simplify.

yanalaym [24]3 years ago
4 0

Answer:

1/16 D

Step-by-step explanation:

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Triangle DEF has sides with lengths of 6, 11, and 13 units. Determine whether this triangle is a right triangle. Show all work n
mario62 [17]

Answer:

Triangle DEF is not a right triangle ; possible lengths are 20 & 15

Step-by-step explanation:

For right triangle;

the sum of the square of the two adjacent sides must equal the square of the hypotenus.

Therefore, (6^2)+(11^2)≠(13^2).

the possible length are 20 & 15 because

(20^2)+(15^2)=(25^2)

8 0
3 years ago
Need help ASAP !!!!<br> Solve for angle A
avanturin [10]
Since vertical angles are equal you can put the same value to the opposite angles. Also, you were given a supplementary angle which are two angles added to 180 degrees. Of those 180 you were given 100. The angle next to the 100 degrees has a value of 80. With all this, you add all the angles together and put it equal to 180 which is what the angles of a triangle add up to. Then you combine like terms to get the value of X and just replace it for x. After that you just multiply and then add.

8 0
3 years ago
A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
kkurt [141]

Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=2b^2+4bh

2b^2+4bh=36

b^2+2bh=18

2bh=18-b^2

h=\frac{18-b^2}{2b}

Volume of box, V=b^2h

Substitute the values

V=b^2\times \frac{18-b^2}{2b}

V=\frac{1}{2}(18b-b^3)

Differentiate w. r.t b

\frac{dV}{db}=\frac{1}{2}(18-3b^2)

\frac{dV}{db}=0

\frac{1}{2}(18-3b^2)=0

\implies 18-3b^2=0

\implies 3b^2=18

b^2=6

b=\pm \sqrt{6}

b=\sqrt{6}

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

At  b=\sqrt{6}

\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}

h=\frac{18-6}{2\sqrt{6}}

h=\frac{12}{2\sqrt{6}}

h=\sqrt{6}

b=h=\sqrt{6} m

7 0
3 years ago
What is length?define​
pogonyaev

Step-by-step explanation:

the measurement or extent of something from end to end; the greater of two or the greatest of three dimensions of an object.

7 0
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Answer:

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