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taurus [48]
3 years ago
6

Please help, (AP is arithemtic progression)

Mathematics
1 answer:
defon3 years ago
7 0

Answer:

p = 8

Step-by-step explanation:

The n th term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₉ = 4 + 5p and d = 5, then

a₁ + 8d = 4 + 5p, that is

a₁ + 8(5) = 4 + 5p

a₁ + 40 = 4 + 5p ( subtract 40 from both sides )

a₁ = 5p - 36

a₂ = 5p - 36 + 5 = 5p - 31

a₃ = 5p - 31 + 5 = 5p - 26

a₄ = 5p - 26 + 5 = 5p - 21

Given that the sum of the first 4 terms = 7p - 10, then

5p - 36 + 5p - 31 + 5p - 26 + 5p - 21 = 7p - 10, that is

20p - 114 = 7p - 10 ( subtract 7p from both sides )

13p - 114 = - 10 ( add 114 to both sides )

13p = 104 ( divide both sides by 13 )

p = 8

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Stephon has a square brick patio. He wants to reduce the width by 4 feet and increase the length by 4 feet.
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Answer:  The expressions for the length and width of the new patio are

\ell=x+4,~~w=x-4.

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The length of one side of the square patio is represented by x.

We are to write the expressions for the length and width of the new patio and then to find the area of the new patio if the original patio measures 20 feet by 20 feet.

Since Stephen wants to reduce width of the patio by 4 feet, so the width of the new patio will be

w=(x-4)~\textup{feet}.

The length of the patio is increased by 4 feet, so the length of the new patio will be

\ell=(x+4)~\textup{feet}.

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w=x-4=20-4=16~\textup{feet}

and

\ell=x+4=20+4=24~\textup{feet}.

Therefore, the area of the new patio is given by

A_n=\ell \times w=24\times16=384~\textup{sq. feet}.

Thus, the expressions for the length and width of the new patio are

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Step-by-step explanation:

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