the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Answer:
Step-by-step explanation:
15.5884573 i
Answer:
the other side would be 15
Step-by-step explanation:
because 15 is bigger than 12 and the 12 is the bottom line and then the other line going up is 15 so it's equal.
The probability that the person pulls 1 blue M&M given that one is only allowed to pull 5 random M&M's per day will be 0.6450.
<h3>How to calculate probability?</h3>
From the information given, there are 1,023 M&M's in a bag and out of 1,023 M&M's, 132 M&M's are blue.
Therefore, the probability of getting a blue M&M will be:
= 132/1023
= 0.1290
Therefore, since the person is given the chance to pull 5 random M&M's per day, the probability will be:
= 0.1290 × 5
= 0.6450
Learn more about probability on:
brainly.com/question/24756209
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