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Sidana [21]
3 years ago
6

Consider 8x2 - 48x = -104.

Mathematics
1 answer:
ki77a [65]3 years ago
7 0

Answer:

3+ 2\mathbf{i}

3- 2\mathbf{i}

Step-by-step explanation:

<u>Quadratic Equation Solving</u>

We have the equation:

8x^2-48x=-104

Divide by 8:

x^2-6x=-13

Now complete the squares so the left side is a perfect square of a binomial:

x^2-6x+9=-13+9=-4

Factoring the perfect square:

(x-3)^2=-4

Taking the square root:

x-3=\sqrt{-4}

The square root of a negative number is an imaginary number:

x-3=\pm 2\mathbf{i}

Solving for x:

x=3\pm 2\mathbf{i}

The solutions are:

3+ 2\mathbf{i}

3- 2\mathbf{i}

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\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}

Step-by-step explanation:

5x^2-x^2e^{2x}+2e^{2x}=10

Let:\ x^2=t  \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}

<em>Prologarithmize both parts of the equation:</em>

ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\

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