It's given in the question,
P, Q, V and K are collinear.
VP = 14x + 4
PK = x + 630
VQ = 17x + 6
KQ = 11x + 5
By segment addition postulate,
KQ + VQ + VP = KP
Substitute the values in the expression,
(11x + 5) + (17x + 6) + (14x + 4) = x + 630
(11x + 17x + 14x) + (5 + 6 + 4) = x + 630
42x + 15 = x + 630
42x - x = 630 - 15
41x = 615
x = 
x = 15
Therefore, value of VP = (14x + 4)
= 14(15) + 4
= 214 units
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brainly.com/question/628239
The answer is 5 buses.
128/30= 4.2....
Round to 5 for the extra children not on the fourth bus.
Answer:
a² + 4ab + 4b²
Step-by-step explanation:
Given
(a + 2b)²
= (a + 2b)(a + 2b)
Each term in the second factor is multiplied by each term in the first factor, that is
a(a + 2b) + 2b(a + 2b) ← distribute both parenthesis
= a² + 2ab + 2ab + 4b² ← collect like terms
= a² + 4ab + 4b²