Can someone help me to answer this please.
1 answer:
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*see attachment for the missing figure
Answer:
Angle ADE = 45°
Angle DAE = 30°
Angle DEA = 105°
Step-by-step explanation:
Since lines AD and BC are parallel, therefore:
Given that angle Angle CBE = 45°,
Angle ADE = Angle CBE (alternate interior angles are congruent)
Angle ADE = 45° (Substitution)
Angle DAE = Angle ACB (Alternate Interior Angles are congruent)
Angle ACB = 180 - 150 (angles on a straight line theorem)
Angle ACB = 30°
Since angle DAE = angle ACB, therefore:
Angle DAE = 30°
Angle DEA = 180 - (angle ADE + angle DAE) (Sum of angles in a triangle)
Angle DEA = 180 - (45 + 30) (Substitution)
Angle DEA = 180 - 75
Angle DEA = 105°
Hello!
First of all we find the slope by dividing the difference of the y values by the difference of the x values as seen below.
The slope of our line is 7/2, or 3.5
-------------------------------------------------------------
Now we will put the slope and a point on our line into slope intercept form and solve for b. We will use (-3,11).
11=3.5(-3)+b
11=10.5+b
b=0.5
Our final equation is shown below.
y=3.5x+0.5
I hope this helps!
First of all we find the slope by dividing the difference of the y values by the difference of the x values as seen below.
The slope of our line is 7/2, or 3.5
-------------------------------------------------------------
Now we will put the slope and a point on our line into slope intercept form and solve for b. We will use (-3,11).
11=3.5(-3)+b
11=10.5+b
b=0.5
Our final equation is shown below.
y=3.5x+0.5
I hope this helps!