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4 years ago

Which expression best represents the product of quantities a, b, and H?

Mathematics

1 answer:

Aleks [24]4 years ago

5 0

Answer:

C) abH

Step-by-step explanation:

a × b × H

= abH

The answer is option C

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Order these from least to greatest 3 39/40 , 3 19/20 , 3 1/2

Lera25 [3.4K]

Hey!

First change all the fractions so that they have a common denominator: 40

$3 \frac{39}{40} = 3 \frac{39}{40}$

$3 \frac{19 \times 2}{20 \times 2} = 3 \frac{38}{40}$

$3 \frac{1 \times 20}{2 \times 20} = 3 \frac{20}{40}$

Now order them:

$3 \frac{39}{40} , 3 \frac{19}{20} , 3 \frac{1}{2}$

Good luck and hope this helps! :)

3 0

3 years ago

Brian buys candy that costs 4 per pound. He will buy at least 8 pounds of candy. What are the possible amounts he will spend on

s2008m [1.1K]

Answer:

32 pound but I dunno what that is in american dollars

8 0

3 years ago

Read 2 more answers

One of the parking lot lights at a hospital has a motion detector on it, and the equation (x+10)2+(y−8)2=16 describes the bounda

Pani-rosa [81]

We are given an equation:
$(x+10)^{2} + (y-8)^{2} = 16$

This is an equation of a circle. General form of a circle equation is:
$(x-a)^{2} + (y-b)^{2} = r^{2}$
Where:
a = x coordinate of a center
b = y coordinate of a center
r = radius of a circle

Motion detector can detect person anywhere within a boundary. The greatest distance at which detector can detect is at the edge of a circle. That distance, between detector and edge of circle, is equal to radius.

From the equation we have:
$r^{2} =16 \\ r=4$
The greatest distance at which person can be detected is 4ft.

7 0

3 years ago

Read 2 more answers

1 Point

I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

<em><u>Ratio for the volumes of two cylinders</u></em>

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$