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DaniilM [7]
3 years ago
6

A spinner has 4 equal sectors colored pink, purple, blue and green. What is the probability of. landing on blue (as a decimal)​

Mathematics
2 answers:
QveST [7]3 years ago
8 0

Answer:

.25

Step-by-step explanation:

It is 0.25 because all you have to do is divide 1 by 4 or 100 by 4 if you want to make it easier then just move the decimal two places. Hope this helps :D

faltersainse [42]3 years ago
6 0

Answer:

0.25

Step-by-step explanation:

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Nataly_w [17]

Answer:

-1.193 <  U_{d}  > 4.443

Step-by-step explanation:

1.625 -1.895 *4.206712/sqr 8

1.625 - \frac{1.895 * 4.206712}{\sqrt{8} }  < U_{d}  >  1.625 +  \frac{1.895 * 4.206712}{\sqrt{8} }  

-1.193 <  U{d}  > 4.443

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Step-by-step explanation:

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A jug has 1 litre of 10% strength cordial. How much pure cordial needs to be added to make the strength 20%?
garik1379 [7]

Answer:

The volume or amount of pure cordial to be added to the solution to make the strength 20% is 125 ml

Step-by-step explanation:

The given parameters, are;

The volume of cordial in the jug = 1 litre

The percentage strength of the cordial = 10%

The proportion of the cordial that contains pure cordial = 0.1

Therefore, the volume of pure cordial in the jug = 0.1 × 1 = 0.1 × 1000 ml = 100 ml

The volume of the solvent = The volume of the solution -  The initial volume of pure cordial

∴ The volume of the solvent = 1000 ml - 100 ml = 900 ml

To increase the concentration of the cordial to 20% is given by the relation;

x/(x+900) = 0.2

Where;

x = The total volume of the pure cordial to be added to the pure solvent

Solving, gives;

x = 0.2×(x+900) = 0.2·x + 180

x -0.2·x = 180

0.8·x = 180

x = 180/0.8 = 225 ml

The total volume of the pure cordial to be added to the pure solvent = x = 225 ml

Therefore, the volume of pure cordial to be added to the initial volume of pure cordial in the solution, which is 100 ml, is therefore given as follows;

The volume or amount of pure cordial to be added = 225 ml - 100 ml = 125 ml.

The volume or amount of pure cordial to be added = 125 ml

8 0
3 years ago
Find the sum of two consecutive odd numbers is 56 find the numbers
ehidna [41]

Answer:

\boxed{\sf 27 \ and \ 29}

Step-by-step explanation:

Let the first consecutive odd integer be \sf x.

Let the second consecutive odd integer be \sf x+2.

The sum of the two numbers is 56.

\sf x+x+2=56

\sf 2x+2=56

\sf 2x=54

\sf x=27

Put x as 27 for the second consecutive odd integer.

\sf 27+2=29

The two numbers are 27 and 29.

3 0
3 years ago
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