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Minchanka [31]
3 years ago
9

A researcher suspects that the actual prevalence of generalized anxiety among children and adolescents is higher than the previo

usly reported prevalence of generalized anxiety disorder among children and adolescents. The previously reported prevalence of generalized anxiety disorder among children and adolescents is 3.9%, and the researcher conducts a study to test the accuracy of the previously reported prevalence of generalized anxiety disorder by recruiting 98 children and adolescents from various pediatricians’ offices and tests them for generalized anxiety disorder using the DSM-5. The researcher determines that the prevalence of generalized anxiety disorder among the participants of the study is 6.1%.
A) For a level of significance of 5%, what should the researcher’s decision rule look like?
Mathematics
2 answers:
Stels [109]3 years ago
7 0

Answer:

Since 6.1% is greater than 5%, the results is statistically insignificant

Step-by-step explanation:

If his observation was to be less than 5% it would have been scientifically significant having confidence level of more than 95%, but 6.1% implies the confidence level is less than 95% and statistically insignificant

Scrat [10]3 years ago
4 0

Answer:

There is insufficient evidence

Step-by-step explanation:

Given : n = 98 p = 0.061 p_0=0.039\alpha=0.05

HYpothesis : H_0:P=0.039 Vs H_1:P>0.039

The test statistic under H o is given by ,

Z=\frac{p-p_0}{\sqrt{p_0q_0/n}}\to N(0,1)

=\frac{0.061-0.039}{\sqrt{0.039*0.961/98}}=1.1250

Critical value : Z_{table }=Z_{\alpha}=Z_{0.05}=1.64

Decision Rule : Here , Z_{stat}=1.1250<Z_{table }=1.64

Therefore , fail to reject H o

Conclusion : Hence , there is insufficient evidence to conclude that the researcher suspects that the actual prevalence of generalized anxiety among children and adolescents is higher than the previously reported prevalence of generalized anxiety disorder among children and adolescents

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matrenka [14]

Factor x^5 - x to get x(x^4 - 1) = x(x^2-1)(x^2+1) = x(x-1)(x+1)(x^2+1)

We see that x = 0, x = 1 and  x = -1 are the real number roots or x intercepts. Ignore the complex or imaginary roots. Unfortunately, the graph shows the x intercepts as -2, 0 and 2 which don't match up.

So there's no way that the given graph matches with f(x) = x^5-x.

-------------------

As more proof, let's consider the end behavior.

As x gets really large toward positive infinity, x^5 will do the same and so will x^5-x. Overall, f(x) will head off to positive infinity. Visually, moving to the right will have the graph move upward forever. This is the complete opposite of what is shown on the graph.

Likewise, the left endpoint should be aimed down instead of up. This is because x^5-x will approach negative infinity as x heads to the left.

In short, the graph shows a "rises to the left, falls to the right" end behavior. It should show a "falls to the left, rises to the right" pattern if we wanted to have a chance at matching it with x^5-x. Keep in mind that matching end behavior isn't enough to get a 100% match; however, having this contradictory end behavior is proof we can rule out a match.

I recommend using Desmos, GeoGebra, or whatever graphing program you prefer to plot out y = x^5-x. You'll get a bettter idea of what's happening.

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