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3 years ago

The perimeter of the polygon above is?

Mathematics

2 answers:

dedylja [7]3 years ago

5 0

The peRIMeter is the length of the RIM of the polygon. So add up all the sides.

9+4+5+10+6+4= 18+20= 38cm

jenyasd209 [6]3 years ago

3 0

Perimeter = the addition of all of the side lengths of the polygon.

The side lengths are 9cm, 6cm, 10cm, 5cm, 4cm, and 4cm.

So the perimeter is the following...

Perimeter = 9 + 6 + 10 + 5 + 4 + 4 = 38cm total

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Find the perimeter of the figure to the nearest hundredth.

Kryger [21]

Hello!

Your answer should be 26.85.

We can use the formula of pi d or 2 pi r for the circumference.

You would get 5 pi.

But since its not a full circle you would divide it in half and get 2.5 pi.

2.5 pi is equal to 7.85.

Now we can use the equation 7.85 + 7 + 7 + 5

That would equal our answer... 26.85!

Hope this helps!

3 0

3 years ago

I need help pleeeeease

Shkiper50 [21]

Answer:

Step-by-step explanation:

because by solving that the answer comes 5.70

7 0

3 years ago

A nurse collected data about the average birth weight of babies in the hospital that month. Her data is shown using the dot plot

mixer [17]

Answer:

The values of the box-plot are: B = {8.2, 8.3, 8.4, 8.5 and 8.9}.

Step-by-step explanation:

The data provided is as follows:

X Frequency

8 0

8.1 0

8.2 2

8.3 2

8.4 2

8.5 3

8.6 0

8.7 1

8.8 0

8.9 1

9 0

So, the actual data is:

S = {8.2 , 8.2 , 8.3 , 8.3 , 8.4 , 8.4 , 8.5 , 8.5 , 8.5 , 8.7 , 8.9 }

A boxplot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

Minimum (shown at the bottom of the chart)
First Quartile (shown by the bottom line of the box)
Median (or the second quartile) (shown as a line in the center of the box)
Third Quartile (shown by the top line of the box)
Maximum (shown at the top of the chart).

The data set is arranged in ascending order.

The minimum value is, Min. = 8.2

The lower quartile is,

$[\frac{n+1}{4}]^{th}\ obs.=[\frac{11+1}{4}]^{th}\ obs.=3^{rd }\ obs. =8.3$ ,

Q₁ = 8.3.

The median value is,

$[\frac{n+1}{2}]^{th}\ obs.=[\frac{11+1}{2}]^{th}\ obs.=6^{th}\ obs.=8.4$

Median = 8.4

The upper quartile is,

$[\frac{3(n+1)}{4}]^{th}\ obs.=[\frac{3(11+1)}{4}]^{th}\ obs.=9^{th }\ obs. =8.5$ ,

Q₃ = 8.5.

The maximum value is, Max. = 8.9.

So, the values of the box-plot are: B = {8.2, 8.3, 8.4, 8.5 and 8.9}.

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=y-5%5Cgeq%20-7" id="TexFormula1" title="y-5\geq -7" alt="y-5\geq -7" align="absmiddle" class="

Monica [59]

If you’re trying to find y the answer should be anything that equals more than negative 7 for example y could be 10

3 0

3 years ago

Read 2 more answers

Solve: -4x-8x+17=23<br> check solution

Sveta_85 [38]

Answer:

x = -1/2

Step-by-step explanation:

To solve the equation, we first need to combine like terms:

$-12x+17=23$

Simplify further:

$-12x=6$

Divide by -12 on both sides to get:

$x = -\frac{1}{2}$

To check the solution, plug x back into the original equation and check if we get the correct answer:

$-4(-\frac{1}{2})-8(-\frac{1}{2})+17=23$

$2+4+17= 23$

$23=23$

Thus, it checks out and our answer is correct.

4 0

3 years ago