Answer:
The length and width of the parking lot is 78 meters and 114 meters respectively.
Step-by-step explanation:
Given;
Perimeter of the parking lot = 
Solution,
Let the width of the parking lot be x.
Then, according to question length = (x-36).
The perimeter of a rectangle is sum of all the sides of rectangle. Which is given by an expression;

Now substituting the values, we get;

Width = 
Length = 
Hence the length and width of the parking lot is 78 meters and 114 meters respectively.
Answer:
Step-by-step explanation:
x = ¼y
y - x = 12
y - ¼y = 12
¾y = 12
y = 16
x = ¼y = 4
Given :
The Mad Hat Company must ship two different-sized boxes: The small ones cost them 45 cents each and weigh 6 ounces, and the large ones weigh 25 ounces and cost $1.20 each.
The total shipment this morning weighed 20 pounds 7 ounces and cost $18.45.
To Find :
How many packages of each size were shipped.
Solution :
We know, 1 pound = 16 ounces.
So, 20 pound = 20×16 = 320 ounces.
Let, number of large and small box are l and s.
So,
25l + 6s = 327 ...1)
0.45s + 1.20l = 18.45 ...2)
Solving both the equations, we get :
x = 9 and y = 17
Therefore, package smaller and big size are 17 and 9 respectively .
Hence, this is the required solution.
Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

Answer:
5676.16 cm^3
Step-by-step explanation:
The volume of any prism is given by the formula ...
V = Bh
where B is the area of one of the parallel bases and h is the perpendicular distance between them. Here, the base is a triangle, so its area will be ...
B = 1/2·bh
where the b and h in this formula are the base and height of the triangle, 28 cm and 22.4 cm.
Then the volume is ...
V = (1/2·(28 cm)(22.4 cm))·(18.1 cm) = 5676.16 cm^3
_____
You will note that this is half the product of the three dimensions, so is half the volume of a cuboid with those dimensions. Perhaps you can see that if you took another such prism and placed the faces having the largest area against each other, you would have a cuboid of the dimensions shown.