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2 years ago

How do you do linear equations?

1 answer:

5 0

To do linear equations, basically, just imagine it with an equals sign. It is pretty much the same as normal algebra, so it's not too confusing.

An example of a linear equation is 3x - 7 = 11
with this, your objective is to get 'x' on its own and to do this, do inverse operations (the opposite to what is actually done)
For instance, to get '3x' on its own, you must add 7.
So do this for both sides to give you

3x = 18
Yeah?

Now you must get 'x' on its own. It currently has 3 x's at the moment, so you must divide it by 3 to give you one 'x'. A rule with these - what you do to one side you must do to the other.
So this means that if you divide 3x by 3, you must divide 18 by 3.

This leaves you with x = 6.

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Divide. Enter the quotient in simplest form. 7 10 ÷ 2 5 =

ruslelena [56]

Answer:

Step-by-step explanation:

ok so if this exuation is 710/25=28.4

but if the exuation is 7*10/2*5=7

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3 years ago

Read 2 more answers

How many kilometers is 23 miles

sladkih [1.3K]

Answer:

37.0149 kilometers

Step-by-step explanation:

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2 years ago

A ball is thrown into the air. The path it takes is modeled by the equation: -3t+24t = h, where t is the time in seconds and h i

astra-53 [7]

Given:

The given equation is:

$-3t^2+24t=h$

Where, t is the time in seconds and h is the height of the ball above the ground, measured in feet.

To find:

The inequality to model when the height of the ball is at least 36 feet above the ground. Then find time taken by ball to reach at or above 36 feet.

Solution:

We have,

$-3t^2+24t=h$

The height of the ball is at least 36 feet above the ground. It means $h\geq 36$ .

$-3t^2+24t\geq 36$

$-3t^2+24t-36\geq 0$

$-3(t^2-8t+12)\geq 0$

Splitting the middle term, we get

$-3(t^2-6t-2t+12)\geq 0$

$-3(t(t-6)-2(t-6))\geq 0$

$-3(t-2)(t-6)\geq 0$

The critical points are:

$-3(t-2)(t-6)=0$

$t=2,6$

These two points divide the number line in 3 intervals $(-\infty,2),(2,6),(6,\infty)$ .

Intervals Check point $-3(t-2)(t-6)\geq 0$ Result

$(-\infty,2)$ 0 $(-)(-)(-)=(-)$ False

$(2,6)$ 4 $(-)(+)(-)=+>0$ True

$(6,\infty)$ 8 $(-)(+)(+)=(-)$ False

The inequality is true for (2,6) and the sign of inequality is $\geq$ . So, the ball is above 36 feet between 2 to 6 seconds.

$6-2=4$

Therefore, the required inequality is $-3t^2+24t\geq 36$ and the ball is 36 feet above for 4 seconds.

3 0

3 years ago

Multiply 6x+3=3(2x+3)

sattari [20]

Answer:

When the distributive property is used on the right side of the equation:

6x + 3 = 6x + 9

**If you wanted to go further by combining like terms, there would no longer be an "x" and all that would be left is 6 or -6, depending on how you combined them**

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3 years ago

What is the decimal expansion for 12 8/9 ?

d1i1m1o1n [39]

Answer:

The decimal form of the fraction is 12.88...

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3 years ago